如何得到CPU的利用率

[Benny_ywb]

已知进程，如何得到该进程的CPU利用率呢？从网上搜了下可以得到系统的CPU，但是没有找到某个进程的方法，想问问相关函数和方法。WINDOWS平台下。

[yc_8301]

上面的函数能否在xp或2000系统下面用啊。

[我啃]

http://topic.csdn.net/t/20011120/22/380241.html
http://blog.csdn.net/wanfustudio/archive/2007/04/07/1555682.aspx

[Benny_ywb]

谢谢啊，我回去试一试。不过博客那个应该是NT平台的吧，WINDOWS也可以调用NtQuerySystemInformation（）吗？

[我啃]

此API是ntdll.dll中没有公开的API
估计98和ME不行

[todototry]

利用ntdll.dll中没有公开的API函数: NtQuerySystemInformation

typedef LONG (WINAPI *PROCNTQSI)(UINT,PVOID,ULONG,PULONG);
PROCNTQSI NtQuerySystemInformation;

NtQuerySystemInformation = (PROCNTQSI)GetProcAddress(
GetModuleHandle("ntdll"),
"NtQuerySystemInformation"
);
if (!NtQuerySystemInformation)
{
return;
}

// get number of processors in the system
status = NtQuerySystemInformation(SystemBasicInformation,
&SysBaseInfo,sizeof(SysBaseInfo),NULL);
if (status != NO_ERROR)
{
return;
}
status = NtQuerySystemInformation(SystemTimeInformation,
&SysTimeInfo,sizeof(SysTimeInfo),0);
if (status!=NO_ERROR)
{
return;
}
// get new CPU''s idle time
status = NtQuerySystemInformation(SystemPerformanceInformation,
&SysPerfInfo,sizeof(SysPerfInfo),NULL);
if (status != NO_ERROR)
{
return;
}
// if it''s a first call - skip it
if (m_liOldIdleTime.QuadPart != 0)
{
// CurrentValue = NewValue - OldValue
dbIdleTime = Li2Double(SysPerfInfo.liIdleTime) - Li2Double(m_liOldIdleTime);
dbSystemTime = Li2Double(SysTimeInfo.liKeSystemTime) - Li2Double(m_liOldSystemTime);

// CurrentCpuIdle = IdleTime / SystemTime
dbIdleTime = dbIdleTime / dbSystemTime;

// CurrentCpuUsage% = 100 - (CurrentCpuIdle * 100) / NumberOfProcessors
dbIdleTime = 100.0 - dbIdleTime * 100.0 / (double)SysBaseInfo.bKeNumberProcessors + 0.5;

m_fNewUsges = (UINT)dbIdleTime;
}