servlet 如何获取form中的参数
我的form
<form action="./uploadMusic" id="fileUploadForm" name="fileUploadForm" method="post" enctype="multipart/form-data" >
<input type="radio" name="musictype" value="0" />
<input type="file" name="file" size="60" />
<input type="submit" name="uploadButton" id="uploadButton" value="上传"/>
</form>
web.xml
<servlet>
<servlet-name>uploadMusic</servlet-name>
<servlet-class>com.ajax.upload.uploadMusic</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>uploadMusic</servlet-name>
<url-pattern>/uploadMusic</url-pattern>
</servlet-mapping>
servlet:
public void doPost(HttpServletRequest request,
HttpServletResponse response) throws ServletException,
IOException {
String musictype = request.getParameter("musictype");
if(musictype==null)musictype="";
System.out.println("-----------------------dopost " +musictype);
}
为什么获取不到musictype 的值呢?
servlet如何获取表单传过来的参数呢?
请各位指教!
谢谢!