jquery 如何取得ajax返回值

[luohailio]

function ajaxCheck(id,innerdiv){
        var value = document.getElementById(id).value;
    url = 'index.php?controller=ajaxcheck&action=Check&ts=' + new Date().getTime();
    params = id + '=' + value;
    //var checkLoader = new zydConnectLoader(url,checkBack,null,"POST",null,innerdiv,null,params,'normal');
    alert( $.ajax({
        data:params,
        beforeSend: function() {
            //alert(params);
        },
        success: function (data) {    
            document.getElementById(innerdiv).innerHTML = data;

        },
        url: url,
        type: "post"
    }));
}

我应该怎样才能通过调用函数ajaxCheck（）取到成功后的data的值

[renyu732]

    var checkExamIsTimer=function()
    {       
	var url="../TEST/ajaxHandler.ashx?action=checkExamIsTimer";
	$.getJSON(url, function(json) {
          alert(json);
           }
        });
    };

[knowledge_Is_Life]

lz要干嘛？

[UltraBejing]

lz要干嘛？