C++面试题

[wpalhm]

判断学生成绩的优劣。用户输入分数，小于60分不及格，60 =< 并且 < 75及格, 75 =< 并且 < 90良好，90 <= 并且
<= 100 优秀。 要求程序中不得出现if、else、while、for、switch关健字，不得使用任何判断、循环语句、不得嵌入汇编

请给个思路！？

[iBug168]

#define __positive(x)    (!((x - 1) & 0x80000000))

#define __D(x)    __positive((60 - x))

#define __C(x)    (__positive(x - 59) && (__positive(75 - x)))

#define __B(x)    ((__positive(x - 74)) && (__positive(90 - x)))

#define __A(x)    ((__positive(x - 89)) && (__positive(100 - x)))

c_result = __D(x) ? 'd' : (__C(x) ? 'c' : (__B(x) ? 'b' : 'a'));

[bitxinhai]

void main()
{

char c[][10] = {"FAIL","PASS","GOOD","EXCELLENT"};
int score;
cout<<"Enter score:"<<endl;
cin>>score;

int a = abs((score-60))+(score-60);
int b = a?((score-60)/15.0+1):0;
cout<<c[b]<<endl;

}
这个程序基本上可以满足要求！！！

[鱼C缸]

很变态

[iBug168]

不得使用任何判断、循环语句

#define __positive(x)    (!((x - 1) & 0x80000000))

#define __D(x)    __positive((60 - x))

#define __C(x)    (__positive(x - 59) && (__positive(75 - x)))

#define __B(x)    ((__positive(x - 74)) && (__positive(90 - x)))

#define __A(x)    ((__positive(x - 89)) && (__positive(100 - x)))

c_result = __D(x) ? 'd' : (__C(x) ? 'c' : (__B(x) ? 'b' : 'a'));

我用abcd表示了4个等级.

[wpalhm]

恩，谢谢。长见识了

[bitxinhai]

#include<iostream.h>

void main()
{
char a[][10] = {"fail","fail","fail","fail","pass","good","excellent"};
cout<<"Enter score:"<<endl;
int score;
cin>>score;

cout<<a[score/15]<<endl;

}
这个程序也是可以的！！！！

[fallening]

[Quote=引用 23 楼 wpalhm 的回复:]
引用 20 楼 fallening 的回复:
还有的，模板的便特化


你能说说思路吗？
[/Quote]

template<size_t SCORE>
string result( )
{
    return result<SCORE-1>();
} 
template<>
string result<0>()
{
    return "Fail";
}
template<>
string result<60>()
{
    return "Pass";
}
template<>
string result<75>()
{
    return "Good";
}
template<>
string result<90>()
{
    return "Excellent";
}

这个思路如何？

[wpalhm]

厉害！csdn上真是牛人一大堆

[fejay]

牛人是多啊!

[zzstv]

阿欧

[GoAssemblyNow]

char* level[101]={"不及格","不及格","不及格","不及格","不及格","不及格","不及格","不及格","不及格","不及格","不及格","不及格","不及格","不及格","不及格","不及格","不及格","不及格","不及格","不及格","不及格","不及格","不及格","不及格","不及格","不及格","不及格","不及格","不及格","不及格","不及格","不及格","不及格","不及格","不及格","不及格","不及格","不及格","不及格","不及格","不及格","不及格","不及格","不及格","不及格","不及格","不及格","不及格","不及格","不及格","不及格","不及格","不及格","不及格","不及格","不及格","不及格","不及格","不及格","及格”，"及格”，"及格”，"及格”，"及格”，"及格”，"及格”，"及格”，"及格”，"及格”，"及格”，"及格”，"及格”，"及格”，"及格”，"及格”， "良好“，"良好“，"良好“，"良好“，"良好“，"良好“，"良好“，"良好“，"良好“，"良好“，"良好“，"良好“，"良好“，"良好“，"良好“，"优秀",优秀",优秀",优秀",优秀",优秀",优秀",优秀",优秀",优秀",优秀",优秀",优秀",优秀",优秀"};

int score;
cin>>score;
cout<<level[score]<<endl;


别拍我哈！

[starliustar]

有意思，见识了

[zwh37333]

解法1 ：递归+ 霍夫曼树 ==〉看数据结构
解法2：TMP 编程，这样也是递归的思想。

[Dazzlingwinter]

这个有意思，呵呵！

[night_legend]

char* level[7]={"不及格","不及格","不及格","不及格","及格","良好","优秀"};

int score;
cin >> score;
cout < < level[score/15] < <endl;
有点取巧,呵呵

[qinqinhao]

ding
ding

[nickkane]

实际开发哪有那么多"不得"啊...bt的要命...

[S7654321]

学习了，牛人就是多

[pustian]

跟37楼一样想法

[yance]

我觉得用cmap类也可以