String literal is not properly closed by a double-quote

y3wegy 2010-05-09 07:38:54

<%@page language="java" contentType="text/html;charset=GB2312"%>
<html>
<body>
<% if(reqest.getParameter("number")!=NULL&&request.getParamter("number")!=" ")
{
int nub=Integer.parseInt(request.getParameter("number"));
int c=((Integer)session.getAttribute("count")).intValue();
int a=((Integer)session.getAttribute("num")).intValue();
if(nub>a)
{
c++;
String s=String.valueof(c);
session.setAttribute("count",s);
response.sendRedirect("1.html");
}
if(nub=a)
{

out.println("恭喜你猜对了，答案是"+a);
out.ptintln("你共用了 "+c+"次);
}
else
{
c++;
String s=String.valueof(c);
session.setAttribute("count",s);
response.sendRedirect("2.html");
}
}
%>
</body>
</html>
运行时时候就出现这个错误
An error occurred at line: 4 in the jsp file: /check.jsp
Generated servlet error:
String literal is not properly closed by a double-quote

org.apache.jasper.servlet.JspServletWrapper.handleJspException(JspServletWrapper.java:512)
org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:377)
org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:314)
org.apache.jasper.servlet.JspServlet.service(JspServlet.java:264)
javax.servlet.http.HttpServlet.service(HttpServlet.java:802)
root cause

org.apache.jasper.JasperException: Unable to compile class for JSP

An error occurred at line: 4 in the jsp file: /check.jsp
Generated servlet error:
String literal is not properly closed by a double-quote

org.apache.jasper.compiler.DefaultErrorHandler.javacError(DefaultErrorHandler.java:84)
org.apache.jasper.compiler.ErrorDispatcher.javacError(ErrorDispatcher.java:328)
org.apache.jasper.compiler.JDTCompiler.generateClass(JDTCompiler.java:414)
org.apache.jasper.compiler.Compiler.compile(Compiler.java:297)
org.apache.jasper.compiler.Compiler.compile(Compiler.java:276)
org.apache.jasper.compiler.Compiler.compile(Compiler.java:264)
org.apache.jasper.JspCompilationContext.compile(JspCompilationContext.java:563)
org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:305)
org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:314)
org.apache.jasper.servlet.JspServlet.service(JspServlet.java:264)
javax.servlet.http.HttpServlet.service(HttpServlet.java:802)
哪位帮我看看啊

...全文

10430 10 打赏收藏转发到动态举报

写回复

用AI写文章

10 条回复

切换为时间正序

请发表友善的回复…

发表回复

liqixi_169 2011-10-11

打赏
举报

楼主太不小心了啊，应该仔细的！！

laker_914 2010-05-10

打赏
举报



session.getAttribute("count")

session.getAttribute("num")

将这两个做一下判断之后再做类型转换吧

justlearn 2010-05-10

打赏
举报

request.getParameter("number")!=" "
比较字符串不要用==
改成"".equals(request.getParameter("number").trim()))

你这个错应该是转换数字出错了，应该是接受的参数不是int型的，所以转换成int出错了

y3wegy 2010-05-09

打赏
举报

不行啊。现在又出现这些
org.apache.jasper.JasperException: Exception in JSP: /check.jsp:11

8: if(request.getParameter("number")!=null&&request.getParameter("number")!=" ")
9: {
10: nub=Integer.parseInt(request.getParameter("number"));
11: c=((Integer)session.getAttribute("count")).intValue();
12: a=((Integer)session.getAttribute("num")).intValue();
13: if(nub>a)
14: {

y3wegy 2010-05-09

打赏
举报

谢了，把我弄晕死了

tfish2014 2010-05-09

打赏
举报

我帮你修改了代码了错误不少啊
你复制我给你修改后的代码吧

<%@ page language="java" import="java.util.*" pageEncoding="gb2312"%>

<html>

<body>

<% 

int nub=0;

int a=0;

int c=0;

if(request.getParameter("number")!=null&&request.getParameter("number")!=" ")

{

  nub=Integer.parseInt(request.getParameter("number"));

  c=((Integer)session.getAttribute("count")).intValue();

  a=((Integer)session.getAttribute("num")).intValue();

  if(nub>a)

  {

  c++;

  String s=String.valueOf(c);

  session.setAttribute("count",s);

  response.sendRedirect("1.html");

  }  

  if(nub==a)

  {

    

  out.println("恭喜你猜对了，答案是"+a);

  out.println("你共用了 "+c+"次");

  }

  else

  {

  c++;

  String s=String.valueOf(c);

  session.setAttribute("count",s);

  response.sendRedirect("2.html");

  }  

}   

%>

</body>

</html>