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public class ThreadA {
public static void main(String[] args) {
ThreadB b = new ThreadB();
b.start();
synchronized (b) {
try {
System.out.println("Waiting for b to complete...");
b.wait();
} catch (InterruptedException e) {
}
System.out.println("Total is: " + b.total);
}
}
}
class ThreadB extends Thread {
int total;
public void run() {
synchronized (this) {
System.out.println("ThreadB");
for (int i = 0; i < 100; i++) {
total += i;
}
notify();
}
}
}
/**
* Causes this thread to begin execution; the Java Virtual Machine
* calls the <code>run</code> method of this thread.
* <p>
* The result is that two threads are running concurrently: the
* current thread (which returns from the call to the
* <code>start</code> method) and the other thread (which executes its
* <code>run</code> method).
* <p>
* It is never legal to start a thread more than once.
* In particular, a thread may not be restarted once it has completed
* execution.
*
* @exception IllegalThreadStateException if the thread was already
* started.
* @see #run()
* @see #stop()
*/
public synchronized void start() {
/**
* This method is not invoked for the main method thread or "system"
* group threads created/set up by the VM. Any new functionality added
* to this method in the future may have to also be added to the VM.
*
* A zero status value corresponds to state "NEW".
*/
if (threadStatus != 0 || this != me)
throw new IllegalThreadStateException();
group.add(this);
start0();
if (stopBeforeStart) {
stop0(throwableFromStop);
}
}
private native void start0();