请问jquery获取json源格式数据？

[xzb_99]

我原来的javascript:

[{"p":"/riskmanagement/UploadFiles/201201/2012012186089097.jpg","l":"http://localhost/riskmanagement/html/?207.html","t":"新年大家都达成心愿，心想事成"},{"p":"/riskmanagement/UploadFiles/201201/2012012178264313.JPG","l":"http://localhost/riskmanagement/html/?206.html","t":"新年好"},]);

现在我想做成动态的，就用了asp,可是不会写了?

$.ajax({							      url: 'http://localhost/riskmanagement/itest.asp',
type: 'GET',
dataType: 'json',											
success:
//请教怎么写？？}
});
};

[001007009]

success: function(data){
//遍历数组就可以了。
}

[xzb_99]

[Quote=引用 1 楼 的回复:]
success: function(data){
//遍历数组就可以了。
}
[/Quote]
是不是这样？
success: function(data){
for(var i in data) {
alert(i+":"+data[i]);
}
}
可是好像没用？

[001007009]

[{"p":"/riskmanagement/UploadFiles/201201/2012012186089097.jpg","l":"http://localhost/riskmanagement/html/?207.html","t":"新年大家都达成心愿，心想事成"},{"p":"/riskmanagement/UploadFiles/201201/2012012178264313.JPG","l":"http://localhost/riskmanagement/html/?206.html","t":"新年好"},]);

你这个格式有问题。

[xzb_99]

[Quote=引用 3 楼 的回复:]
[{"p":"/riskmanagement/UploadFiles/201201/2012012186089097.jpg","l":"http://localhost/riskmanagement/html/?207.html","t":"新年大家都达成心愿，心想事成"},{"p":"/riskmanagement/UploadFiles/201201/2012012178264313.JPG……
[/Quote]
已经改成这样了：
[{"p":"/riskmanagement/UploadFiles/201201/2012012186089097.jpg","l":"http://localhost/riskmanagement/html/?207.html","t":"新年大家都达成心愿，心想事成"},{"p":"/riskmanagement/UploadFiles/201201/2012012178264313.JPG","l":"http://localhost/riskmanagement/html/?206.html","t":"新年好"}]
还是不行

[001007009]

success: function(data){
data = data[0];
for(var i in data) {
alert(i+":"+data[i]);
}
}