如何统计一个字符串内有多少个数字和英文字母

[yonghot]

在网上找了一个，可能System中没有包含Character这个类，所以，没注意了。
求各位帮忙看一眼。谢谢。

[PandaIT]

很简单 提供思路 用ascii码判断就好

[Banianer]

你对字符做一个单个截取的循环，判断该字符是否在 ascii码 数字和英文的范围之内，如果是
则统计+1 最后输出统计变量。

[threenewbee]

string s = "hello csdn, hello 404.";
var query = from x in s.ToUpper() group x by x >= 'A' && x <= 'Z' ? 0 : (x >= '0' && x <= '9' ? 1 : 2) into g select new { type = g.Key, count = g.Count() };
Console.WriteLine("字母有{0}个", query.Where(x => x.Type == 0).Single().count);
Console.WriteLine("数字有{0}个", query.Where(x => x.Type == 1).Single().count);
Console.WriteLine("其它有{0}个", query.Where(x => x.Type == 2).Single().count);

[人生难得一只鸡]

正则 试试

string test = "abCdef12tf356我们都是7";
                int count1 = Regex.Matches(test,@"\d").Count;// 数字个数：6
                int count2 = Regex.Matches(test, @"(?i)[a-z]").Count;//字母个数：8
                int count3 = Regex.Matches(test, @"[\u4e00-\u9fa5]").Count;//汉字个数：4

[cloudapex]

string str = "另顶戴枯aslkdfjasf345sdfa";

char[] arr = str.ToCharArray();

int number = 0;
int english = 0;

foreach (char c in arr)
{
int i = c + 0;

if (i > 47 && i < 58)
number++;
else if ((i > 64 && i < 91) || (i > 96 && i < 123))
english++;
}

Console.WriteLine(string.Format("原字符串：{0}\r\n数字：{1} 个\r\n字母：{2} 个", str, number, english));

Console.Write("\n按任一键结束...");
Console.ReadKey();

[threenewbee]

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;

namespace ConsoleApplication1
{
    class Program
    {
        static void Main(string[] args)
        {
            string s = "hello csdn, hello 404.";
            var query = from x in s.ToUpper() group x by x >= 'A' && x <= 'Z' ? 0 : (x >= '0' && x <= '9' ? 1 : 2) into g select new { type = g.Key, count = g.Count() };
            Console.WriteLine("字母有{0}个.", query.Where(x => x.type == 0).Single().count);
            Console.WriteLine("数字有{0}个.", query.Where(x => x.type == 1).Single().count);
            Console.WriteLine("其它有{0}个.", query.Where(x => x.type == 2).Single().count);
        }
    }
}

字母有14个.
数字有3个.
其它有5个.
Press any key to continue . . .

[haojuntu]

[Quote=引用 1 楼 的回复:]

很简单 提供思路 用ascii码判断就好
[/Quote]

用的一楼方法，结果没有问题

  //i1字母数量、i2数字数量、i3其它
            int i1=0, i2=0, i3=0;
            string temp = "abcdefghij852为什么417";
            foreach (char item in temp)
            {
                int i = (int)item;
                if (i > 47 && i < 58)
                    i2++;
                else if ((i > 96 && i < 123) || (i > 64 && i < 91))
                    i1++;
                else
                    i3++;
            }
            string result = string.Format("字母数量:{0},数字数量:{1},文字数量:{2}",i1,i2,i3);
            Console.WriteLine(result);
            Console.ReadLine();

[xiedu414]

[Quote=引用 4 楼 的回复:]
正则 试试

C# code
string test = "abCdef12tf356我们都是7";
int count1 = Regex.Matches(test,@"\d").Count;// 数字个数：6
int count2 = Regex.Matches(test, @"(?i)[a-z]").Count;//字母……
[/Quote]
+1

[chen_ya_ping]

string str = "1ah234b100A";
            Regex regex = new Regex("[0-9]");
            Console.WriteLine(regex.Matches(str).Count);
            Console.WriteLine("-----------------------");
            regex = new Regex("[a-z,A-Z]");
            Console.WriteLine(regex.Matches(str).Count);

[csdn_风中雪狼]

[Quote=引用 4 楼 的回复:]
正则 试试

C# code

string test = "abCdef12tf356我们都是7";
int count1 = Regex.Matches(test,@"\d").Count;// 数字个数：6
int count2 = Regex.Matches(test, @"(?i)[a-z]").Count;//……
[/Quote]

用正则来实现吧