c++复数类问题

[dixuexiongyingss]

用c++我写了个CComplexNumber（复数类），在主函数内我写了CComplexNumber CComplexNumber1 = 2这个语句主要是为了让对象的实部等于2，虚部等于0，我该怎么做，该重载哪个函数或运算符，请各位大侠多多指教，先行谢过啦！

[yisikaipu]

标准库直接就有复数类

#include <complex>
using namespace std;

int main()
{
	complex<double> c1(2,0);
	return 0;
}

[dixuexiongyingss]

还有一个问题就是在main函数里我又写了一句：int i = CComplexNumber1;这句话该怎么做才能编译过呢？希望大家再次赐教，感谢2楼提供的方法，非常正确，谢谢！！！

[dixuexiongyingss]

已经解决了，非常感谢各位关注并解决这个问题。

[pathuang68]

这个问题的回答可大可小...参考下面的代码：

#include <iostream>
using namespace std;

class CComplexNumber
{
private:
	double realPart;
	double imaginaryPart;

public:
	CComplexNumber()
	{
		realPart = 0.0;
		imaginaryPart = 0.0;
	}

	CComplexNumber(int realPart)	// 隐式类型转换
	{
		this->realPart = (double)realPart;
		imaginaryPart = 0.0;
	}

	CComplexNumber(double realPart, double imaginaryPart)
	{
		this->realPart = realPart;
		this->imaginaryPart = imaginaryPart;
	}

	CComplexNumber operator+(CComplexNumber& aComplexNumber)
	{
		CComplexNumber temp;
		temp.realPart = realPart + aComplexNumber.realPart;
		temp.imaginaryPart = imaginaryPart + aComplexNumber.imaginaryPart;
		return temp;
	}

	 friend ostream& operator << (ostream&, const CComplexNumber&);
};

ostream& operator << (ostream& os, const CComplexNumber& aComplexNumber)
{
	if(aComplexNumber.imaginaryPart == 0.0)
	{
		os << aComplexNumber.realPart;
	}
	else if(aComplexNumber.imaginaryPart > 0.0)
	{
		os << aComplexNumber.realPart << "+" << aComplexNumber.imaginaryPart << "i";
	}
	else
	{
		os << aComplexNumber.realPart << aComplexNumber.imaginaryPart << "i";
	}

	return os;
}

int main(int argc, char** argv)
{
	CComplexNumber CComplexNumber1 = 2;
	CComplexNumber CComplexNumber2(1.1, 2.2);

	cout << CComplexNumber1 + CComplexNumber2 << endl;

	return 0;
}

关于隐式类型转换可以参考： 隐式类型转换和explicit关键字的作用