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re.findall(r'\d+', str)
src = "hhh:394892m skdjfslsdjf"
cc = re.match(".+?(\d+)", src)
if cc is not None:
print cc.group(1)
>>> import re
>>> s = ' hhh:394892m skdjfslsdjf'
>>> res = r'\S(\d+)m'
>>> print re.findall(res,s)
['394892']
>>>