求助，SQL 统计写法！

[编程的微小小]

各位朋友，本人求教一个SQL写法，有个表里面有,（回访日期，很好，较好，一般，接车，机电，钣金，美容，销售）等字段，除“回访日期”外其它字段类型都是"BIT" 现在想，统计一个是间段内，的（很好，较好，一般，接车，机电，钣金，美容，销售）等字段值为"true"的统计汇总，
昨天求助论坛的朋友，得出写法：

select sum(case 很好 when 1 then 1 else 0 end) as sum_很好，
sum(case 较好 when 1 then 1 else 0 end) as sum_较好，
sum(case 一般 when 1 then 1 else 0 end) as sum_一般，
sum(case 接车 when 1 then 1 else 0 end) as sum_接车，
sum(case 机电 when 1 then 1 else 0 end) as sum_机电，
sum(case 钣金 when 1 then 1 else 0 end) as sum_钣金，
sum(case 美容 when 1 then 1 else 0 end) as sum_美容，
sum(case 销售 when 1 then 1 else 0 end) as sum_销售  from table

得到的结果是：
sum_很好 sum_较好 sum_一般 sum_接车 sum_机电 sum_钣金 sum_美容 sum_销售
10 20 30 10 5 12 13 14

结果是正确的，但不符合我要的显示方式：
我想使这呈现:

评价类型 得分
SUM_很好 10
SUM_较好 20
sum_一般 30
sum_接车 10
sum_机电 5
sum_钣金 12
sum_美容 13
sum_销售 14
请问该如何实现？ 谢谢！

[水族杰纶]

UNPIVOT http://technet.microsoft.com/zh-cn/library/ms177410.aspx

[唐诗三百首]

try this,

select c '评价类型',x '得分'
 from (select 
        sum(case 很好 when 1 then 1 else 0 end) as sum_很好,
        sum(case 较好 when 1 then 1 else 0 end) as sum_较好,
        sum(case 一般 when 1 then 1 else 0 end) as sum_一般,
        sum(case 接车 when 1 then 1 else 0 end) as sum_接车,
        sum(case 机电 when 1 then 1 else 0 end) as sum_机电,
        sum(case 钣金 when 1 then 1 else 0 end) as sum_钣金,
        sum(case 美容 when 1 then 1 else 0 end) as sum_美容,
        sum(case 销售 when 1 then 1 else 0 end) as sum_销售  
       from [table]) a
 unpivot
 (x for c in([sum_很好],[sum_较好],[sum_一般],[sum_接车],[sum_机电],[sum_钣金],[sum_美容],[sum_销售])) p

[编程的微小小]

很棒，谢谢朋友们！

[xiaoqi7456]

SELECT 'sum_很好',sum(case 很好 when 1 then 1 else 0 end) FROM table 
UNION ALL
SELECT 'sum_较好',sum(case 较好 when 1 then 1 else 0 end) FROM table 

以此类推

[發糞塗牆]

 SELECT 'sum_很好' 评价类型 ,
        SUM(CASE 很好
              WHEN 1 THEN 1
              ELSE 0
            END) 得分
 FROM   [table]
 UNION ALL
 SELECT 'sum_较好' 评价类型 ,
        SUM(CASE 较好
              WHEN 1 THEN 1
              ELSE 0
            END) 得分
 FROM   [table]
 UNION ALL
 SELECT 'sum_一般' 评价类型 ,
        SUM(CASE 一般
              WHEN 1 THEN 1
              ELSE 0
            END) 得分
 FROM   [table]
 UNION ALL
 SELECT 'sum_接车' 评价类型 ,
        SUM(CASE 接车
              WHEN 1 THEN 1
              ELSE 0
            END) 得分
 FROM   [table]
 UNION ALL
 SELECT 'sum_机电' 评价类型 ,
        SUM(CASE 机电
              WHEN 1 THEN 1
              ELSE 0
            END) 得分
 FROM   [table]
 UNION ALL
 SELECT 'sum_钣金' 评价类型 ,
        SUM(CASE 钣金
              WHEN 1 THEN 1
              ELSE 0
            END) 得分
 FROM   [table]
 UNION ALL
 SELECT 'sum_美容' 评价类型 ,
        SUM(CASE 美容
              WHEN 1 THEN 1
              ELSE 0
            END) 得分
 FROM   [table]
 UNION ALL
 SELECT 'sum_销售' 评价类型 ,
        SUM(CASE 销售
              WHEN 1 THEN 1
              ELSE 0
            END) 得分
 FROM   [table]