myeclipse 第一个程序就不能运行，请各位帮忙指教

Mike的小山 2013-07-11 06:18:12

刚装的myeclipse2013 all-in-one，建立web project工程和程序servlet文档结构如图

程序内容：

import java.io.IOException;
import java.io.PrintWriter;

import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;

public class HelloServlet extends HttpServlet {

/**
* Constructor of the object.
*/
public HelloServlet() {
super();
}

/**
* Destruction of the servlet. <br>
*/
public void destroy() {
super.destroy(); // Just puts "destroy" string in log
// Put your code here
}

/**
* The doGet method of the servlet. <br>
*
* This method is called when a form has its tag value method equals to get.
*
* @param request the request send by the client to the server
* @param response the response send by the server to the client
* @throws ServletException if an error occurred
* @throws IOException if an error occurred
*/
public void doGet(HttpServletRequest request, HttpServletResponse response)
throws ServletException, IOException {

request.setCharacterEncoding("UTF-8");
response.setCharacterEncoding("UTF-8");
response.setContentType("text/html");
PrintWriter out = response.getWriter();
out.println("<!DOCTYPE HTML PUBLIC \"-//W3C//DTD HTML 4.01 Transitional//EN\">");
out.println("<HTML>");
out.println(" <HEAD><TITLE>A Servlet</TITLE></HEAD>");
out.println(" <BODY>");String requestURI=request.getRequestURI();
out.println("<form action='"+requestURI+"' method='post'>");
out.println("Input your name:<input type='text' name='name'/>");
out.println("<input type='submit'/>");
out.println("</form>");
out.println("");

String name=request.getParameter("name");
if(name!=null && name.trim().length()>0){
out.println("Hello,<b>"+name+"</b>.");
out.println(" </BODY>");
out.println("</HTML>");
out.flush();
out.close();
}
}

/**
* The doPost method of the servlet. <br>
*
* This method is called when a form has its tag value method equals to post.
*
* @param request the request send by the client to the server
* @param response the response send by the server to the client
* @throws ServletException if an error occurred
* @throws IOException if an error occurred
*/
public void doPost(HttpServletRequest request, HttpServletResponse response)
throws ServletException, IOException {

response.setContentType("text/html");
PrintWriter out = response.getWriter();
out.println("<!DOCTYPE HTML PUBLIC \"-//W3C//DTD HTML 4.01 Transitional//EN\">");
out.println("<HTML>");
out.println(" <HEAD><TITLE>A Servlet</TITLE></HEAD>");
out.println(" <BODY>");
out.print(" This is ");
out.print(this.getClass());
out.println(", using the POST method");
out.println(" </BODY>");
out.println("</HTML>");
out.flush();
out.close();
}

/**
* Initialization of the servlet. <br>
*
* @throws ServletException if an error occurs
*/
public void init() throws ServletException {
// Put your code here
}

}

web.xml为自动生成，内容：
<?xml version="1.0" encoding="UTF-8"?>
<web-app version="3.0"
xmlns="http://java.sun.com/xml/ns/javaee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd">
<servlet>
<description>This is the description of my J2EE component</description>
<display-name>This is the display name of my J2EE component</display-name>
<servlet-name>HelloServlet</servlet-name>
<servlet-class>com.mikedehill.firstweb.HelloServlet</servlet-class>
</servlet>

<servlet-mapping>
<servlet-name>HelloServlet</servlet-name>
<url-pattern>/servlet/HelloServlet</url-pattern>
</servlet-mapping>

</web-app>

tomcat可以启动
2013-7-11 16:53:57 org.apache.tomcat.util.digester.SetPropertiesRule begin
警告: [SetPropertiesRule]{Server/Service/Engine/Host/Context} Setting property 'source' to 'org.eclipse.jst.jee.server:FirstWeb' did not find a matching property.
2013-7-11 16:53:58 org.apache.catalina.core.AprLifecycleListener initializeSSL
信息: OpenSSL successfully initialized (OpenSSL 1.0.1d 5 Feb 2013)
2013-7-11 16:53:59 org.apache.coyote.AbstractProtocol init
信息: Initializing ProtocolHandler ["http-apr-8080"]
2013-7-11 16:53:59 org.apache.coyote.AbstractProtocol init
信息: Initializing ProtocolHandler ["ajp-apr-8009"]
2013-7-11 16:53:59 org.apache.catalina.startup.Catalina load
信息: Initialization processed in 3969 ms
2013-7-11 16:53:59 org.apache.catalina.core.StandardService startInternal
信息: Starting service Catalina
2013-7-11 16:53:59 org.apache.catalina.core.StandardEngine startInternal
信息: Starting Servlet Engine: Apache Tomcat/7.0.40
2013-7-11 16:54:01 org.apache.catalina.startup.HostConfig deployDirectory
信息: Deploying web application directory D:\Program Files\apache-tomcat-7.0.40\webapps\DeployCopy
2013-7-11 16:54:02 org.apache.catalina.startup.HostConfig deployDirectory
信息: Deploying web application directory D:\Program Files\apache-tomcat-7.0.40\webapps\docs
2013-7-11 16:54:02 org.apache.catalina.startup.HostConfig deployDirectory
信息: Deploying web application directory D:\Program Files\apache-tomcat-7.0.40\webapps\examples
2013-7-11 16:54:02 org.apache.catalina.core.ApplicationContext log
信息: ContextListener: contextInitialized()
2013-7-11 16:54:02 org.apache.catalina.core.ApplicationContext log
信息: SessionListener: contextInitialized()
2013-7-11 16:54:02 org.apache.catalina.core.ApplicationContext log
信息: ContextListener: attributeAdded('org.apache.jasper.compiler.TldLocationsCache', 'org.apache.jasper.compiler.TldLocationsCache@1a05bdb')
2013-7-11 16:54:02 org.apache.catalina.startup.HostConfig deployDirectory
信息: Deploying web application directory D:\Program Files\apache-tomcat-7.0.40\webapps\host-manager
2013-7-11 16:54:03 org.apache.catalina.startup.HostConfig deployDirectory
信息: Deploying web application directory D:\Program Files\apache-tomcat-7.0.40\webapps\manager
2013-7-11 16:54:03 org.apache.catalina.startup.HostConfig deployDirectory
信息: Deploying web application directory D:\Program Files\apache-tomcat-7.0.40\webapps\ROOT
2013-7-11 16:54:03 org.apache.coyote.AbstractProtocol start
信息: Starting ProtocolHandler ["http-apr-8080"]
2013-7-11 16:54:03 org.apache.coyote.AbstractProtocol start
信息: Starting ProtocolHandler ["ajp-apr-8009"]
2013-7-11 16:54:03 org.apache.catalina.startup.Catalina start
信息: Server startup in 3952 ms

1、按小三角运行按钮显示：the serve is not specified

2、用浏览器键入：http://localhost:8080/FirstWeb/servlet/HelloServlet后回车，显示：
HTTP Status 404 - /FirstWeb/servlet/HelloServlet

--------------------------------------------------------------------------------

type Status report

message /FirstWeb/servlet/HelloServlet

description The requested resource is not available.

--------------------------------------------------------------------------------

Apache Tomcat/7.0.40

请教各位，这个程序应该如何才能编译运行？

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lkq_david 2013-07-16

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项目没部署好吧，访问你的端口号，看看小猫头能不能出来

Mike的小山 2013-07-16

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引用 17 楼 u011238857 的回复:

1、工具栏windows->showview->servers
2、servers视图，右键选择Add and Remove
3、选择你的项目添加到server
4、点击三角运行

是这样吗，还是不行

风中的木头 2013-07-15

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1、工具栏windows->showview->servers 2、servers视图，右键选择Add and Remove 3、选择你的项目添加到server 4、点击三角运行

Mike的小山 2013-07-15

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引用 15 楼 u011237944 的回复:

[quote=引用 6 楼 Yuan_Rong_Hua 的回复:] 是你项目没部署成功到的原因，你看你tomcat控制台输出信息，自带的root，manage等都都有输出信息，没有你的firstWeb,你重新部署一下，然后点击run as server application

现在知道是tomcat的问题，但具体在哪不知道。myeclipse自带tomcat7（原来不知道），我将程序部署在自带tomcat7上即可访问了。那么为什么我引入的外部tomcat7.x可以在mycelipse中运行，却不能成功部署程序？谁知道？我希望程序在两个tomcat中都能运行。[/quote] 打错了，是为什么。。。

Mike的小山 2013-07-15