Thu, 21 Aug 2014 19:15:12 +0800 (CST) 时间格式化

Jaeson_Chen 2014-08-21 07:34:28

如题所示获取到的时间字符串”Thu, 21 Aug 2014 19:15:12 +0800 (CST)“，需要用C语言进行格式化为这样子的字符串：
2014-08-21 19：15：12 ，请问是否有相关函数？或者该如何进行转换？

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Jaeson_Chen 2014-11-06

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引用 5 楼 zhao4zhong1 的回复:

仅供参考：

#include <stdio.h>
#include <string.h>
#include <time.h>
#include <time.h>
#include <sys/timeb.h>

struct tm st;
time_t tt;
char mon[4];
char mn[12][4]={"Jan","Feb","Mar","Apr","May","Jun","Jul","Aug","Sep","Oct","Nov","Dec"};
int i;
char timstr[27];
char tmpbuf[128];
struct _timeb tb;
int tz;
char c;

void main() {
    strcpy(timstr,"08/Dec/2011:15:25:03 +0800");
    sscanf(timstr,"%2d/%3s/%4d:%2d:%2d:%2d",&st.tm_mday,mon,&st.tm_year,&st.tm_hour,&st.tm_min,&st.tm_sec);
    for (i=0;i<12;i++) if (0==stricmp(mn[i],mon)) {st.tm_mon=i; break;}
    st.tm_year-=1900;
    tt=mktime(&st);
    if (-1!=tt) {
        strftime(tmpbuf,128,"%Y-%m-%d %H:%M:%S\n",localtime(&tt));
        printf(tmpbuf);//2011-12-08 15:25:03
    } else {
        printf("[%s] is Invalid time string!\n",timstr);
    }

    _ftime(&tb);
    strftime(tmpbuf,128,"%m/%b/%Y:%H:%M:%S",localtime(&tb.time));
    tz=-tb.timezone;
    c=(tz>0)?'+':'-';
    tz=(tz>0)?tz:-tz;
    sprintf(tmpbuf,"%s %c%02d%02d\n",tmpbuf,c,tz/60,tz%60);
    printf(tmpbuf);//12/Dec/2011:17:36:41 +0800
}

忘记结贴了，非常感谢你！！

Jaeson_Chen 2014-08-22

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多谢，总监的对C不了解，一定要我掉函数，我欲哭无泪，自己已写好了

707wk 2014-08-22

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引用 5 楼 zhao4zhong1 的回复:

仅供参考：

#include <stdio.h>
#include <string.h>
#include <time.h>
#include <time.h>
#include <sys/timeb.h>

struct tm st;
time_t tt;
char mon[4];
char mn[12][4]={"Jan","Feb","Mar","Apr","May","Jun","Jul","Aug","Sep","Oct","Nov","Dec"};
int i;
char timstr[27];
char tmpbuf[128];
struct _timeb tb;
int tz;
char c;

void main() {
    strcpy(timstr,"08/Dec/2011:15:25:03 +0800");
    sscanf(timstr,"%2d/%3s/%4d:%2d:%2d:%2d",&st.tm_mday,mon,&st.tm_year,&st.tm_hour,&st.tm_min,&st.tm_sec);
    for (i=0;i<12;i++) if (0==stricmp(mn[i],mon)) {st.tm_mon=i; break;}
    st.tm_year-=1900;
    tt=mktime(&st);
    if (-1!=tt) {
        strftime(tmpbuf,128,"%Y-%m-%d %H:%M:%S\n",localtime(&tt));
        printf(tmpbuf);//2011-12-08 15:25:03
    } else {
        printf("[%s] is Invalid time string!\n",timstr);
    }

    _ftime(&tb);
    strftime(tmpbuf,128,"%m/%b/%Y:%H:%M:%S",localtime(&tb.time));
    tz=-tb.timezone;
    c=(tz>0)?'+':'-';
    tz=(tz>0)?tz:-tz;
    sprintf(tmpbuf,"%s %c%02d%02d\n",tmpbuf,c,tz/60,tz%60);
    printf(tmpbuf);//12/Dec/2011:17:36:41 +0800
}

zhuyf87 2014-08-22

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”Thu, 21 Aug 2014 19:15:12 +0800 (CST)“，如果格式固定的话，自己转很简单，最基本的c语言编程。总监还管你调用哪个函数？

边走边瞧 2014-08-22

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引用 4 楼 chenxiong815 的回复:

多谢，总监的对C不了解，一定要我掉函数，我欲哭无泪，自己已写好了

你们总监很有才啊，这么个细节也要关注一下。

赵4老师 2014-08-22

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仅供参考：

#include <stdio.h>
#include <string.h>
#include <time.h>
#include <time.h>
#include <sys/timeb.h>

struct tm st;
time_t tt;
char mon[4];
char mn[12][4]={"Jan","Feb","Mar","Apr","May","Jun","Jul","Aug","Sep","Oct","Nov","Dec"};
int i;
char timstr[27];
char tmpbuf[128];
struct _timeb tb;
int tz;
char c;

void main() {
    strcpy(timstr,"08/Dec/2011:15:25:03 +0800");
    sscanf(timstr,"%2d/%3s/%4d:%2d:%2d:%2d",&st.tm_mday,mon,&st.tm_year,&st.tm_hour,&st.tm_min,&st.tm_sec);
    for (i=0;i<12;i++) if (0==stricmp(mn[i],mon)) {st.tm_mon=i; break;}
    st.tm_year-=1900;
    tt=mktime(&st);
    if (-1!=tt) {
        strftime(tmpbuf,128,"%Y-%m-%d %H:%M:%S\n",localtime(&tt));
        printf(tmpbuf);//2011-12-08 15:25:03
    } else {
        printf("[%s] is Invalid time string!\n",timstr);
    }

    _ftime(&tb);
    strftime(tmpbuf,128,"%m/%b/%Y:%H:%M:%S",localtime(&tb.time));
    tz=-tb.timezone;
    c=(tz>0)?'+':'-';
    tz=(tz>0)?tz:-tz;
    sprintf(tmpbuf,"%s %c%02d%02d\n",tmpbuf,c,tz/60,tz%60);
    printf(tmpbuf);//12/Dec/2011:17:36:41 +0800
}