关于$post datatype:json出错,真心求教,自己已经瞎搞差不多一天了
HTML
<input id="add0" name="id" type="hidden" value="<?php echo $archive->id;?>"/>
<input id="add0" name="title" type="hidden" value="<?php echo $archive->title;?>"/>
<input id="add0" name="priceper" type="hidden" value="<?php echo $archive->thisprice;?>"/>
<input id="add0" name="dw" type="hidden" value="<?php echo $archive->thisunit;?>"/>
<input id="add0" name="parentid" type="hidden" value="<?php echo $archive->parentid;?>"/>
<input id="add0" name="image" type="hidden" value="<?php echo $archive->thispic0;?>"/>
<input id="add0" type="text" name="querity" class="spinnerExample"/>
<a href="javascript:void(0);" class="buyitnow" style="text-decoration: none; color:#fff;">立即购买</a>
<script>
$(document).ready(function(){
$(".buyitnow").click(function(){
var cont=$("#add0").serialize();
var id=$("#myform input[name='id']").val();
var title=$('#myform input[name="title"]').val();
var priceper=$("#myform input[name='priceper']").val();
var querity=$("#myform input[name='querity']").val();
var dw=$("#myform input[name='dw']").val();
var parentid=$("#myform input[name='parentid']").val();
var image=$("#myform input[name='image']").val();
$.ajax({
url:"myorder_sub.php",
type:"post",
data:cont,
dataType:"json",
success:function(data){
alert(data.title);
window.location.href="<?php echo base_url();?>index.php/member/post/myorder_sub";
},
error:function(){
alert('失败');
}
});
});
})
</script>
接收程序代码
<?php
$id=$_POST['id'];
$title=$_POST['title'];
$priceper=$_POST['priceper'];
$querity=$_POST['querity'];
$dw=$_POST['dw'];
$parentid=$_POST['parentid'];
$image=$_POST['image'];
$json_arr = array("id"=>$id,"title"=>$title,"priceper"=>$priceper,"querity"=>$querity,"price"=>$price,"dw"=>$dw,"parentid"=>$parentid,"image"=>$image);
$json_obj = json_encode($json_arr);
echo $json_obj;
?>
我jQuery刚学,都做到想哭了,求大神指教