带参数类的引用，新人求指教

[Chris_Hsu]

最近刚开始学习Java，类的构造，函数的构造之类的还不是很明白。
下面这个程序编译的时候有如下错误：
Manager.java: 13: error: constructor Employee in class Employee connot be applied to given types:
Employee em=new Employee("Chris");
^
required: no arguments
found: String
reason: actual and formal argument lists differ in length.
但是在class Employee的构造函数中已经有参数了啊，所以不太明白，求帮忙。

class Employee{
	public String name;
	public void Employee(String n){
		name=n;
	}
}
public class Manager{
	public static void main(String [] args){
		Employee em=new Employee("Chris");
		System.out.println(em.name);
	}
}

public class Employee{
	public String name;
	public void Employee(String n){
		name=n;
	}
	public static void main(String [] args){
		Employee em=new Employee("Chris");
		System.out.println(em.name);
	}
}

[qzw1210]

public class Employee{
	public String name;
        public Employee(String name){//带String的构造方法
               this.name=name;
        }
	public void Employee(String n){
		name=n;
	}
	public static void main(String [] args){
		Employee em=new Employee("Chris");
		System.out.println(em.name);
	}
}

[Chris_Hsu]

引用 1 楼 qu1210 的回复:

public class Employee{
	public String name;
        public Employee(String name){//带String的构造方法
               this.name=name;
        }
	public void Employee(String n){
		name=n;
	}
	public static void main(String [] args){
		Employee em=new Employee("Chris");
		System.out.println(em.name);
	}
}

谢谢二楼，刚在网上查了，构造函数不能有返回值，不能带void，你是第一个回复的，谢谢啦！