请教各位大神查询问题

yschat2012 2015-01-18 11:17:45

	int categoryid = Integer.parseInt(request.getParameter("id"));

		String keyWord = request.getParameter("keyWord");

		// 获取当前页

		String currPage = request.getParameter("currPage");

		String hql = "from Info d ";

		Object[] where = null;

		String action = request.getContextPath() + "/baseData/med.do?command=blurQuery";

		// 转码

		if (currPage != null && !currPage.isEmpty()) {

			keyWord = StringUtil.encodeZh(keyWord);

		}

		if (keyWord != null && !keyWord.isEmpty()) {

			action += "&keyWord=" + StringUtil.encodeURL(keyWord);

			keyWord = "%" + keyWord + "%";

			

			hql += " where d.categoryId like ? or d.title like ? or d.description like ?";

			where = new Object[] {categoryid,keyWord, keyWord };

		}

		// 分页查询

		Map map = this.getPage(hql, recPerPage, currPage, action, where);

错误提示：
could not resolve property: categoryId of: com.lyq.persistence.Info [select count(*) from com.lyq.persistence.Info d where d.categoryId like ? or d.title like ? or d.description like ?]
我查了下Info类，有categoryId啊
public class Info {

private int id; //id号
private String title;
private int categoryId;
不过它是与其他表关联的约束字段，配置代码如下：

<hibernate-mapping package="com.lyq.persistence">

	<class name="Info" table="tb_info">

		<!-- 主键 -->

		<id name="id">

			<generator class="native"/>

		</id>

	

		<property name="title" not-null="true" />

	……

		<!-- 与类别的多对一关系 -->

		<many-to-one name="Category" column="categoryId" cascade="save-update"/>

	</class>

是不是这个问题？该怎么解决？谢谢！！

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