困扰我一天的struts第一个程序

冰蓝色狂想曲 2015-05-13 09:53:41

我想做一个简单的登录功能，一共有三个页面，全部放在\WebContent文件夹下，分别是
index.jsp



<%@ page contentType="text/html; charset=UTF-8" %>

<%@ taglib prefix="s" uri="/struts-tags" %>

<html>

<head>

<title>index.jsp</title>

</head>

<body>

index body

</body>

</html>

<%@ page contentType="text/html; charset=UTF-8" %>

<%@ taglib prefix="s" uri="/struts-tags" %>

<html>

<head>

    <title>login</title>

</head>



<body>

<s:form action="login" namespace="/">

    <s:textfield key="username"/>

    <s:password key="password" />

    <s:submit/>

</s:form>

</body>

</html>

welcome.jsp

<%@ page language="java" contentType="text/html; charset=ISO-8859-1"

    pageEncoding="ISO-8859-1"%>

<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">

<html>

<head>

<meta http-equiv="Content-Type" content="text/html; charset=ISO-8859-1">

<title>welcome</title>

</head>

<body>

welcome

</body>

</html>

两个配置文件web.xml，放在WebContent\WEB-INF文件夹下



<?xml version="1.0" encoding="UTF-8"?>

<web-app id="WebApp_9" version="2.4" xmlns="http://java.sun.com/xml/ns/j2ee"

         xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"

         xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd">



    <display-name>Struts Blank</display-name>



    <filter>

        <filter-name>struts2</filter-name>

        <filter-class>org.apache.struts2.dispatcher.ng.filter.StrutsPrepareAndExecuteFilter</filter-class>

    </filter>



    <filter-mapping>

        <filter-name>struts2</filter-name>

        <url-pattern>/*</url-pattern>

    </filter-mapping>



    <welcome-file-list>

        <welcome-file>index.jsp</welcome-file>

    </welcome-file-list>





</web-app>

struts.xml，在编译后自动生成到/WEB-INF\classes文件夹中

<?xml version="1.0" encoding="UTF-8" ?>

<!DOCTYPE struts PUBLIC

	"-//Apache Software Foundation//DTD Struts Configuration 2.3//EN"

	"http://struts.apache.org/dtds/struts-2.3.dtd">



<struts>



    <constant name="struts.enable.DynamicMethodInvocation" value="false" />

    <constant name="struts.devMode" value="true" />

    

	<package name="default" namespace="/" extends="struts-default" >

		<action name="login" class="com.emmashomes.struts2.action.LoginAction">

	    	<result name="success">welcome.jsp</result>

	    	<result name="login">login.jsp</result>

	    </action>

	</package>





</struts>

一个处理函数LoginAction.java



package com.emmashomes.struts2.action;

import com.opensymphony.xwork2.ActionSupport;





public class LoginAction extends ActionSupport{



	private static final long serialVersionUID = 1L;



	private String username;

	private String password;

	public String getUsername() {

		return username;

	}

	public void setUsername(String username) {

		this.username = username;

	}

	public String getPassword() {

		return password;

	}

	public void setPassword(String password) {

		this.password = password;

	}

	

	public String excute() {

		System.out.println(" LoginAction excute() ");

		if( "123".equals(username) && "123".equals(password) ) {

			System.out.println(SUCCESS);

			return SUCCESS;

		}

		System.out.println(LOGIN);

		return LOGIN;

	}

}

我想要的结果是，打开login.jsp页面时，当输入帐号密码都为123时，则进入welcome.jsp页面；否则进入login.jsp页面。
现在的问题是，当打开logIn.jsp页面时：
1）会出现警告: Missing key [username] in bundles [[org/apache/struts2/struts-messages, com/opensymphony/xwork2/xwork-messages]]!
2）不管用户名密码输入什么，都会进入welcome.jsp页面
3）函数中的System.out.println()语句完全没有执行。

我知道这个问题对于大神们很简单真心求教但新手入门真心痛苦求教

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