求助：json + java 返回 数据 数组中去掉双引号

[hrbsf]

现在返回的数据：
[{"name":"jack","data":["11","22","33","44"]},{"name":"rose","data":["11","22","33","44"]}]

我想通过 java 后台处理下，返回的数据为：

[{"name":"jack","data":[11,22,33,44]},{"name":"rose","data":[11,22,33,44]}]

后台我如果不用转换 则所有 都不带双引号

getlistmapMsg = JsonTools.getJsonString("json:", Chartlistmap);


未转换 [{name=jack, data=[11, 22, 33, 44]}, {name=rose, data=[11, 22, 33, 44]}]

[予_远方]

额，这样的话，不知道正则可不可以。BUT俺对正则不懂啊。坐等大神

[解开者]

那就不能当做json来处理了，用正则匹配吧：

		String s = "[{\"name\":\"jack\",\"data\":[\"11\",\"22\",\"33\",\"44\"]},{\"name\":\"rose\",\"data\":[\"11\",\"22\",\"33\",\"44\"]}]";
		String regex = "\"(\\d+)\"";
		Pattern pattern = Pattern.compile(regex);
		Matcher matcher = pattern.matcher(s);
		while (matcher.find()) {
			String group = matcher.group();
			s = s.replace(group, group.substring(1, group.length() - 1));
		}
		System.out.println(s);

[hrbsf]

引用 2 楼 windowsoahil 的回复:

那就不能当做json来处理了，用正则匹配吧：

		String s = "[{\"name\":\"jack\",\"data\":[\"11\",\"22\",\"33\",\"44\"]},{\"name\":\"rose\",\"data\":[\"11\",\"22\",\"33\",\"44\"]}]";
		String regex = "\"(\\d+)\"";
		Pattern pattern = Pattern.compile(regex);
		Matcher matcher = pattern.matcher(s);
		while (matcher.find()) {
			String group = matcher.group();
			s = s.replace(group, group.substring(1, group.length() - 1));
		}
		System.out.println(s);

感谢朋友！ 大神啊！谢谢！谢谢！