一道某公司的面试题，一起来试试把

[玉怀一捧雪]

#include <stdio.h>

int main(void)
{
	char *str[] = {"welcome","to","fortemedia","Nanjing"};	
	char **p = str+1;
	str[0] = (*p++)+2;
	str[1] = *(p+1);
	str[2] = p[1]+3;
	str[3] = p[0] + (str[2]-str[1]);
	printf("%s\n",str[0]);
	printf("%s\n",str[1]);
	printf("%s\n",str[2]);
	printf("%s\n",str[3]);
	return 0;
}

输出打印内容

[91program]

void TestPoint(void)
{
	char *str[] = {"welcome","to","fortemedia","Nanjing"};    
	char **p = str+1;		// to
	str[0] = (*p++)+2;		// 先运行 () 中的,再 +2,后 p 等于 fortemedia
	str[1] = *(p+1);
	str[2] = p[1]+3;
	str[3] = p[0] + (str[2]-str[1]);
	printf("%s\n",str[0]);		// NULL
	printf("%s\n",str[1]);		// Nanjing
	printf("%s\n",str[2]);		// jing
	printf("%s\n",str[3]);		// g
}