php 从二维数组找出不一样的值并且count（）这个有多少个

[baoxuri]

$shuliang=explode(",",$fxida);
var_dump($shuliang);
echo count($shuliang);
现在已经找出来二维数组了。
array (size=11)
0 => string '1' (length=1)
1 => string '1' (length=1)
2 => string '1' (length=1)
3 => string '1' (length=1)
4 => string '1' (length=1)
5 => string '1' (length=1)
6 => string '1' (length=1)
7 => string '1' (length=1)
8 => string '1' (length=1)
9 => string '2' (length=1)
10 => string '1' (length=1)
现在我要做的是 找到等于2的并且统计等于2的有多少个。

[xuzuning]

$t = array_count_values($shuliang);
echo $t['2'];

[傲雪星枫]

array_count_values 方法可以 http://php.net/manual/zh/function.array-count-values.php

$shuliang=explode(",",$fxida);
 var_dump($shuliang);
echo count($shuliang);
$result = array_count_values(shuliang);
print_r($result);