使用ssm框架时，怎么在登录的时候把user_login.action改为user_login.html？？？

西门吹雪吹吹风 2016-08-05 09:03:13

--urlrewrite.xml

<?xml version="1.0" encoding="utf-8"?>    

<!DOCTYPE urlrewrite PUBLIC "-//tuckey.org//DTD UrlRewrite 2.6//EN"    "http://tuckey.org/res/dtds/urlrewrite2.6.dtd" >



<>

	<rule>

		<from>/index.html</from>

		<to type="forward">/index.jsp</to>

	</rule>

	<rule>

		<from>/([a-zA-Z0-9_\u4e00-\u9fa5]+).html</from>

		<to type="forward">/ssmTest/$1.action</to>

	</rule>

</urlrewrite>

---web.xml

<?xml version="1.0" encoding="UTF-8"?>

<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://java.sun.com/xml/ns/javaee" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd" id="WebApp_ID" version="3.0">

  <context-param>

    <param-name>contextConfigLocation</param-name>

    <param-value>classpath:spring*.xml</param-value>

  </context-param>

  <listener>

    <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>

  </listener>

  <filter>

    <filter-name>struts2</filter-name>

    <filter-class>org.apache.struts2.dispatcher.filter.StrutsPrepareAndExecuteFilter</filter-class>

  </filter>

  <filter-mapping>

    <filter-name>struts2</filter-name>

    <url-pattern>/*</url-pattern>

    <dispatcher>REQUEST</dispatcher>

    <dispatcher>FORWARD</dispatcher>

  </filter-mapping>

  

  <filter>  

    <filter-name>UrlRewriteFilter</filter-name>  

    <filter-class>org.tuckey.web.filters.urlrewrite.UrlRewriteFilter</filter-class>  

</filter>  

<filter-mapping>  

    <filter-name>UrlRewriteFilter</filter-name>  

    <url-pattern>/*</url-pattern>  

</filter-mapping> 

<welcome-file-list>

	<welcome-file>index.jsp</welcome-file>

	<welcome-file>*.html</welcome-file>

</welcome-file-list>

</web-app>