spring+jpa+em.persist(student)不能把student对象持久化到Mysql数据中，程序运行也不报错，但可以查到数据

[S_O_T]

请各位大神帮忙解决一个问题：
spring+jpa+em.persist(student)不能把student对象持久化到Mysql数据中，程序运行也不报错，但可以查到数据库中原有数据，这是什么原因啊？谢谢！（我是新手，对jpa还不太熟悉）

spring配置：

<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
	xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" 
	xmlns:tx="http://www.springframework.org/schema/tx"
	xmlns:jdbc="http://www.springframework.org/schema/jdbc"
	xsi:schemaLocation="http://www.springframework.org/schema/jdbc http://www.springframework.org/schema/jdbc/spring-jdbc-3.2.xsd
		http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans.xsd
		http://www.springframework.org/schema/tx http://www.springframework.org/schema/tx/spring-tx-3.1.xsd">

	<bean id="jdbc"
		class="org.springframework.beans.factory.config.PropertiesFactoryBean">
		<property name="locations" value="classpath:/dev/jdbc.properties"></property>
	</bean>
	<bean id="dataSource"
		class="org.springframework.jdbc.datasource.DriverManagerDataSource">
		<property name="driverClassName" value="#{jdbc.driverClassName}"></property>
		<constructor-arg value="#{jdbc.url}"></constructor-arg>
		<constructor-arg value="#{jdbc.userName}"></constructor-arg>
		<constructor-arg value="#{jdbc.password}"></constructor-arg>
	</bean>
	<bean id="emf"
		class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean">
		<description>
			..........
		</description>
		<property name="dataSource" ref="dataSource" />
		<property name="persistenceUnitName" value="default" />
		<property name="packagesToScan">
			<list>
				<value>com.wyiwei.entity_modle.infrastructur.shared.modle</value>
			</list>
		</property>
		<property name="jpaVendorAdapter">
			<bean class="org.springframework.orm.jpa.vendor.HibernateJpaVendorAdapter">
				<property name="generateDdl" value="true" />
				<property name="showSql" value="false" />
			</bean>
		</property>
	</bean>
	

<!-- 	<bean class="org.springframework.jdbc.core.JdbcTemplate"> -->
<!-- 		<property name="dataSource" ref="dataSource" /> -->
<!-- 	</bean> -->

	<bean id="transactionManager" class="org.springframework.orm.jpa.JpaTransactionManager">
		<property name="entityManagerFactory" ref="emf" />
	</bean>

<!-- 	<tx:annotation-driven  -->
<!-- 		transaction-manager="transactionManager" proxy-target-class="true"/> -->
	<tx:annotation-driven mode="aspectj"
		transaction-manager="transactionManager" />
</beans>

实体类：

@Entity
@Table(name="STUDENT")
public class Student implements Serializable{

	private static final long serialVersionUID = -4022855296927067776L;

	@Id
    @Column(name="STU_SEQ", nullable=false)
    private Integer stuSeq;

    @Column(name="STUDENT_NAME", nullable=false, length=21)
    private String studentName;
    
    @Column(name="STU_AGE", nullable=false, length=4)
    private Integer stuAge;
    
	public Integer getStuSeq() {
		return stuSeq;
	}

	public void setStuSeq(Integer stuSeq) {
		this.stuSeq = stuSeq;
	}

	public String getStudentName() {
		return studentName;
	}

	public void setStudentName(String studentName) {
		this.studentName = studentName;
	}

	public Integer getStuAge() {
		return stuAge;
	}

	public void setStuAge(Integer stuAge) {
		this.stuAge = stuAge;
	}

	@Override
	public String toString() {
		return "Student [stuSeq=" + stuSeq + ", studentName=" + studentName
				+ ", stuAge=" + stuAge + "]";
	}

    
}

测试代码：

@ContextConfiguration({ "/test-context.xml"})
public class PersistTest extends AbstractTest{

	@PersistenceContext
	private EntityManager em;

	@Test
	public void test(){
		
//		query();
		
		persist();
		
		System.out.println("Over!");
	}

	@Transactional
	private void persist(){
		Student s = new Student();

		s.setStuAge(30);
		s.setStudentName("张三");
		s.setStuSeq(1);

		em.persist(s);
	}

	@Transactional
	private void query(){
		QStudent q = QStudent.student;

		Student student = new JPAQuery(em).from(q).where(q.stuSeq.eq(1)).uniqueResult(q);

		System.out.println(student);


	}