在java中使用c语言中byte数组类型的rsa公钥进行加密的问题

小安安 2016-12-16 09:33:41
c中有一组公钥:
其中byte类型为unsigned char类型
typedef unsigned char byte;
byte pub_key[] = {0x30,0x82,0x02,0x5c,0x02,0x01,0x00,0x02,0x81,0x81,0x00,0xcb,0x69,0x37,0x7b,0x34
,0x03,0x4e,0xb8,0x41,0x72,0x75,0xcb,0xcf,0x6a,0x13,0x76,0x6b,0x2a,0x4b,0x3c,0x6e
,0xc1,0x26,0x17,0x34,0x01,0xdd,0x2e,0x1f,0xd6,0x81,0x1f,0xba,0x93,0x39,0x73,0x2a
,0xeb,0x32,0x06,0xb9,0x62,0xf4,0xd2,0xbb,0x16,0x74,0xba,0x2e,0xfd,0x39,0x1e,0x1e
,0x1d,0xdb,0xe8,0x81,0x8a,0x92,0xa3,0x83,0xec,0x16,0x79,0x57,0x6a,0x0b,0x9b,0x52
,0x30,0xd5,0x95,0x85,0xf4,0x0d,0x0a,0x0b,0x8e,0xb5,0x5d,0x9d,0xb8,0x93,0xa2,0x17
,0x16,0xe9,0x95,0x29,0x91,0x1d,0xb0,0x0c,0x3c,0xfb,0xab,0x10,0xf1,0x06,0xd0,0x0e
,0x49,0xb2,0x55,0xba,0x00,0x09,0x70,0x63,0xf2,0x8a,0x42,0x8f,0x23,0x4c,0xb2,0xb2
,0x7c,0xf1,0x7e,0x05,0x92,0xb9,0xe4,0x2c,0xf2,0x3d,0xab,0x02,0x03,0x01,0x00,0x01
,0x02,0x81,0x81,0x00,0xab,0x60,0x8a,0x8e,0x12,0xd4,0x76,0x8e,0x67,0x15,0xb8,0x89
,0x6e,0xc7,0x40,0x7e,0x94,0xeb,0x9d,0x57,0xdd,0x38,0x7e,0x8f,0x2e,0x12,0x23,0xf7
,0xa8,0x7b,0x61,0x6f,0x0a,0x12,0xe0,0x64,0x57,0xd4,0xb0,0xe1,0x59,0x70,0x36,0x35
,0x15,0xcb,0x65,0xad,0x37,0xc9,0xc1,0x45,0xce,0xb9,0xf9,0x7d,0x7b,0x26,0xf5,0x45
,0x2e,0xf0,0xca,0x3d,0x0f,0xf2,0xb0,0x6a,0x88,0xd9,0x48,0x7d,0x23,0x8b,0x6c,0xb0
,0xcf,0x50,0xb7,0x9c,0x71,0x1d,0x04,0x3d,0x59,0x0f,0x97,0x0e,0x82,0xae,0x15,0xc8
,0xa0,0xe9,0x27,0x95,0x97,0x2a,0x78,0xa3,0x97,0x4f,0xd1,0xf9,0x55,0xb0,0xa8,0x4e
,0x9d,0x70,0x80,0x35,0xbe,0xb6,0x6d,0x2c,0x11,0x32,0xca,0x55,0xe7,0x68,0xb5,0x8b
,0xcc,0x99,0x96,0x81,0x02,0x41,0x00,0xf6,0x59,0x76,0x8f,0xb0,0x23,0xa5,0x2f,0x59
,0x9f,0xcc,0x10,0x08,0xa2,0xb7,0xb8,0x8e,0x66,0x42,0x08,0x8f,0xff,0x3e,0x6c,0x48
,0xee,0x19,0x73,0x0b,0xae,0x1a,0xb8,0x39,0xa0,0xc1,0xf0,0x48,0x06,0xa5,0xca,0xc2
,0xd6,0xb5,0x01,0xda,0x82,0x46,0xee,0x22,0xe2,0x9b,0xd1,0xc6,0x25,0xcd,0x80,0x2a
,0xb3,0x30,0x87,0x01,0xc3,0xbf,0xef,0x02,0x41,0x00,0xd3,0x61,0x24,0x3a,0x79,0x02
,0xf2,0x21,0x92,0xe1,0xdd,0x71,0x50,0x49,0x34,0x67,0x5f,0xe9,0xb2,0xba,0xb3,0x05
,0xa4,0x58,0x02,0xff,0xa1,0x3f,0xca,0x3f,0xc3,0x0f,0x2f,0x24,0xdf,0xb3,0x1e,0x13
,0xad,0x9f,0x54,0x6f,0x70,0xc5,0xbf,0x5f,0x5c,0x4c,0xc9,0x84,0x37,0x0f,0xaa,0x40
,0x04,0x46,0x9e,0x6b,0xf9,0xe0,0x4f,0xba,0x62,0x05,0x02,0x40,0x1a,0xa3,0xbc,0x05
,0x77,0xc7,0xb3,0x02,0x36,0xcf,0xe7,0xf2,0x47,0xec,0xc8,0xaf,0x45,0x7e,0xdb,0x5f
,0x2f,0xab,0x2b,0x65,0xec,0x51,0x0b,0x21,0x7c,0xbe,0xdc,0x16,0xd5,0xec,0x83,0x6c
,0x67,0x6d,0x88,0x9a,0x2f,0x8d,0xa6,0x4f,0x48,0x00,0xd4,0x88,0xc5,0xee,0xf9,0x68
,0xaa,0xe3,0xc5,0xa0,0x39,0x7d,0xdd,0x1e,0x8c,0x5b,0x4d,0xb3,0x02,0x40,0x29,0x2a
,0x42,0xde,0xec,0x50,0x29,0x8d,0x66,0x48,0x7c,0x52,0xa3,0xfb,0x0d,0xac,0x90,0x1e
,0x38,0x03,0x69,0xf7,0xd0,0x50,0x9f,0x8c,0xde,0xff,0x48,0x48,0xf0,0x98,0xd5,0x6a
,0x8d,0xf2,0x19,0x0a,0x66,0x06,0xa0,0x6f,0xef,0x7b,0x63,0x50,0x93,0xee,0x14,0x54
,0x9e,0x50,0x7b,0xac,0x69,0xe8,0xc2,0xd3,0x6e,0x5f,0x43,0xc7,0x9d,0x6d,0x02,0x40
,0x6f,0x9d,0x01,0xe3,0x70,0x57,0xf2,0x1f,0xfa,0x52,0x8a,0x3e,0xa6,0x1d,0x38,0xe1
,0x62,0x46,0xda,0xf6,0xcf,0x49,0x4c,0xf3,0x60,0xe5,0xa3,0x6b,0x3e,0x0a,0x9d,0x42
,0xc3,0xa1,0x41,0xa8,0x14,0x7c,0xb7,0x44,0x5f,0x64,0x7f,0x79,0xba,0xb8,0x80,0xf2
,0x94,0x92,0xc1,0x4f,0xab,0xb5,0xae,0xbe,0x1b,0xc5,0x6e,0x9c,0x11,0x99,0xf7,0xdb};


请问一下在java中如何使用这组公钥进么rsa加密? 要求不用jni,原生java来写!
求问


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【课程介绍】     课程目标:             - 有状态登录和无状态登录的区别             - 常见的非对称加密算法和非对称的加密方式             - 老版本只使用jwt进行加密的弊端             - 授权心的授权流程             - 如何整合网关组件实现jwt安全验证             - 理解什么是公钥什么是私钥      - 深刻理解授权流程什么是有状态? 有状态服务,即服务端需要记录每次会话的客户端信息,从而识别客户端身份,根据用户身份进行请求的处理,典型的设计如tomcat的session。例如登录:用户登录后,我们把登录者的信息保存在服务端session,并且给用户一个cookie值,记录对应的session。然后下次请求,用户携带cookie值来,我们就能识别到对应session,从而找到用户的信息。缺点是什么?- 服务端保存大量数据,增加服务端压力- 服务端保存用户状态,无法进行水平扩展- 客户端请求依赖服务端,多次请求必须访问同一台服务器。什么是无状态? 微服务集群的每个服务,对外提供的都是Rest风格的接口。而Rest风格的一个最重要的规范就是:服务的无状态性,即:- 服务端不保存任何客户端请求者信息- 客户端的每次请求必须具备自描述信息,通过这些信息识别客户端身份带来的好处是什么呢?- 客户端请求不依赖服务端的信息,任何多次请求不需要必须访问到同一台服务- 服务端的集群和状态对客户端透明- 服务端可以任意的迁移和伸缩- 减小服务端存储压力

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