javascript中的数组的问题

[小明明明明明]

题目是这个：
Given an array of integers, return indices of the two numbers such that they add up to a specific target.

You may assume that each input would have exactly one solution, and you may not use the same element twice.

Example:
Given nums = [2, 7, 11, 15], target = 9,

Because nums[0] + nums[1] = 2 + 7 = 9,
return [0, 1].


我的答案：

/**
 * @param {number[]} nums
 * @param {number} target
 * @return {number[]}
 */
function twoSum(nums, target) {
  nums.forEach(function(num,i) {
        var index =  nums.indexOf(target - num);
        if(index !== -1 && index !== i){
            return [index,i];
            
        }
    });
}

请问为什么达不到想要的效果呀

[swing wang]

没怎么看懂题的意思，看看这样行不行

function getResult(integers,target){
  for(var i in integers){
    for(var j =0; j<integers.length;j++){
      if(integers[i]+integers[j]==target){
        retrun [i,j];
      }
    }
  }
}

[Go 旅城通票]

return是forEach的返回值又不是你函数的

    function twoSum(nums, target) {
        var rst=null////////////
        nums.forEach(function (num, i) {
            var index = nums.indexOf(target - num);
            if (index !== -1 && index !== i) {
                rst= [index, i];//////////

            }
        });
        return rst;///////////
    }

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[冬狮郎sun]

leetcode上面第一题，我的答案

/**
 * @param {number[]} nums
 * @param {number} target
 * @return {number[]}
 */
var twoSum = function(nums, target) {
    for(var i = 0,len = nums.length;i<len;i++){
        for(var j = i+1;j<len;j++){
            if(nums[i]+nums[j] == target){
                return [i,j];
            }
        }
    }
};

[75闪光雷]

你为什么不自己写for循环呢？