2个外部中断计数窜口通信

xiaolongx 2017-08-31 04:55:38
用89C52单片机，2个外部脉冲信号分别计数，将结果由窜口输出到PC。我试了多次，单个中断可行，2个则不行，请教！

#include<reg52.h>
#include<Stdio.h>
#define duan P0
#define uchar unsigned char
#define uint unsigned int
sbit wei1=P2^4;
sbit wei2=P2^5;
sbit wei3=P2^6;
sbit wei4=P2^7;
sbit LED =P1^0;
uchar code tab[]={0x3f,0x06,0x5b,0x4f,0x66,0x6d,0x7d,0x07,0x7f,0x6f};
uint num1=0,num2=0,ge,shi,bai,qian;
uchar UART_buff,SEND_buff[8];
bit New_rec = 0, Send_ed = 1, Start = 0;
void SendString(unsigned char *p);

//----------------------------------------------
void delay(unsigned int i) //Delay
{
unsigned int j;
for(i;i>0;i--)
for(j = 112; j >0; j--);
}
//----------------------------------------------
void display() //display
{
duan=tab[ge];
wei1=0;
wei2=0;
wei3=0;
wei4=1;
delay(5);
duan=tab[shi];
wei1=0;
wei2=0;
wei3=1;
wei4=0;
delay(5);
duan=tab[bai];
wei1=0;
wei2=1;
wei3=0;
wei4=0;
delay(5);
duan=tab[qian];
wei1=1;
wei2=0;
wei3=0;
wei4=0;
delay(5);
}
//----------------------------------------------
void main (void)
{
SCON = 0x50;
TMOD = 0x20;
TH1 = 0xFD;
TL1 = 0xFD;
TR1 = 1;
ES= 1; //port interrupt
EA=1; //sum interrupt

EX0=1; //out interrupt 0
IT0=1; //1-down edge ,0-low
PX0=1; //First

EX1=1; //out interrupt 1
IT1=1; //1-down edge ,0-low
PX1=0; //second

while(1)
{
display();
if ((New_rec == 1) && (Send_ed == 1))
{
New_rec = 0;
Send_ed = 0;
}
}
}

//----------------------------------------------
void int0() interrupt 0 //sensor1 interrupt
{
num1++;
//sprintf(SEND_buff,"%8d",num1,"\n");
printf(SEND_buff,"%s : %s",num1,num2);
ge=num1%10;
shi=num1/10%10;
bai=num2%10;
qian=num2/10%10;
if(num1==99)
num1=0;
}

//----------------------------------------------
void int1() interrupt 1 //sensor2 interrupt
{
num2++;
//sprintf(SEND_buff,"%8d",num2,"\n");
printf(SEND_buff,"%s : %s",num1,num2);
ge=num1%10;
shi=num1/10%10;
bai=num2%10;
qian=num2/10%10;
if(num2==99)
num2=0;
}
//----------------------------------------------
void ser_int (void) interrupt 4 //serial port
{
if(RI == 1)
{
RI = 0; //recive string
New_rec = 1;
UART_buff = SBUF;
if(UART_buff == '#')
{ LED = 1,num1=0,num2=0;
//sprintf(SEND_buff,"%8d",num1,"\n");
sprintf(SEND_buff,"%s : %s",num1,num2);
}
else if(UART_buff == '$')
{ LED = 0;
SendString(SEND_buff);
}
else if(UART_buff == '%')
{ LED = 0;
SendString(SEND_buff);
}
}
else
{
SendString(SEND_buff); //send string
TI = 0;
Send_ed = 1;
}
//delay(200);
//while(P3^2==0);
}
void SendChar(unsigned char Chr)
{
SBUF=Chr;
while(!TI);
TI=0;
}
void SendString(unsigned char *p)
{
while(*p)
{
SendChar(*p);
p++;
}
}
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tianxj001 2017-09-01
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char num1=78; char num2=56; char SEND_buff[8]; sprintf(SEND_buff,"=m",num1,num2); 运行后 SEND_buff[]=“78 96” 这样，SEND_buff数组里面就已经是字符串内容的2个计数数据了。
依然冷暖 2017-09-01
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stdio带一个sprintf()函数 直接把内容变成字符串
tianxj001 2017-08-31
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2 个结果，我看你貌似在个十百千已经进行处理了啊，这个个十百千应该是你显示程序用的变量吧，里你所谓的拼接是指？串口输出数据拼接?
xiaolongx 2017-08-31
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引用 2 楼 tianxj001 的回复:
#include<reg52.h>
#include<Stdio.h>
#define duan P0
#define uchar unsigned char
#define uint unsigned int
sbit wei1=P2^4;
sbit wei2=P2^5;
sbit wei3=P2^6;
sbit wei4=P2^7;
sbit LED1=P2^0;
sbit LED2=P2^1;
uchar code tab[]={0x3f,0x06,0x5b,0x4f,0x66,0x6d,0x7d,0x07,0x7f,0x6f};
uint num1=0,num2=0,ge,shi,bai,qian;
uchar UART_buff,SEND_buff[8];
bit New_rec = 0, Send_ed = 1, Start = 0;
void SendString(unsigned char *p);

//----------------------------------------------
void delay(unsigned int i)      //Delay
{
  unsigned int j;
  for(i;i>0;i--)
        for(j = 112; j >0; j--);
}
//----------------------------------------------
void display()                    //display
{
  	duan=tab[ge];
wei1=0;
wei2=0;
wei3=0;
wei4=1;
delay(5);
duan=tab[shi];
wei1=0;
wei2=0;
wei3=1;
wei4=0;
delay(5);
duan=tab[bai];
wei1=0;
wei2=1;
wei3=0;
wei4=0;
delay(5);
duan=tab[qian];
wei1=1;
wei2=0;
wei3=0;
wei4=0;
delay(5);
}
//----------------------------------------------
void main (void)
{
    SCON = 0x50;  
    TMOD = 0x20; 
    TH1 = 0xFD; 
    TL1 = 0xFD;
    TR1 = 1;                        
    ES= 1;     //port interrupt
EA=1;      //sum interrupt

    EX0=1;	   //out interrupt 0
    IT0=1;	   //1-down edge ,0-low 
PX0=1;     //First

    EX1=1;	   //out interrupt 1
    IT1=1;	   //1-down edge ,0-low 
PX1=0;     //second

    while(1)  
 { 
display();	
      if ((New_rec == 1) && (Send_ed == 1))  
{  	
New_rec = 0;
Send_ed = 0;
        }
      }
}

//----------------------------------------------
void int0() interrupt 0    //sensor1 interrupt
{
 LED1=~LED1;
//   num1++;
// //sprintf(SEND_buff,"%8d",num1,"\n");
// printf(SEND_buff,"%s : %s",num1,num2);
//   ge=num1%10;
//   shi=num1/10%10;
//   bai=num2%10;
//   qian=num2/10%10;
//   if(num1==99)
//   num1=0;
}

//----------------------------------------------
void int1() interrupt 1    //sensor2 interrupt
{
    LED2=~LED2;
//   num2++;
// //sprintf(SEND_buff,"%8d",num2,"\n");
// printf(SEND_buff,"%s : %s",num1,num2);
//   ge=num1%10;
//   shi=num1/10%10;
//   bai=num2%10;
//   qian=num2/10%10;
//   if(num2==99)
//   num2=0;
}
//----------------------------------------------
void ser_int (void) interrupt 4    //serial port
{
    if(RI == 1) 
{ 
      RI = 0;              //recive string
      New_rec = 1;
      UART_buff = SBUF; 
      if(UART_buff == '#')
{ //LED = 1,num1=0,num2=0;
//sprintf(SEND_buff,"%8d",num1,"\n");
sprintf(SEND_buff,"%s : %s",num1,num2);
            }
else if(UART_buff == '$') 
{ //LED = 0;
SendString(SEND_buff);
}
else if(UART_buff == '%') 
{ //LED = 0;
SendString(SEND_buff);
     	}
      }
    else 
  { 
  SendString(SEND_buff);     //send string
      TI = 0;  
      Send_ed = 1;
    }
//delay(200);
  //while(P3^2==0);
} 
void SendChar(unsigned char Chr)
{	
SBUF=Chr;
while(!TI);
TI=0;
}
void SendString(unsigned char *p)
{
while(*p)
{
SendChar(*p);
p++;
}
}
修改了几个地方，为了快速测试，在PROTEUS上面仿真通过
双中断工作解决了，现在问题： 如何将两个结果拼接成一窜字符输出？
tianxj001 2017-08-31
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2个按钮分别可以反转D1 D2状态，说明下降沿中断正确执行
tianxj001 2017-08-31
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#include<reg52.h>

#include<Stdio.h>

#define duan P0

#define uchar unsigned char

#define uint unsigned int

sbit wei1=P2^4;

sbit wei2=P2^5;

sbit wei3=P2^6;

sbit wei4=P2^7;

sbit LED1=P2^0;

sbit LED2=P2^1;

uchar code tab[]={0x3f,0x06,0x5b,0x4f,0x66,0x6d,0x7d,0x07,0x7f,0x6f};

uint num1=0,num2=0,ge,shi,bai,qian;

uchar UART_buff,SEND_buff[8];

bit New_rec = 0, Send_ed = 1, Start = 0;

void SendString(unsigned char *p);



//----------------------------------------------

void delay(unsigned int i)      //Delay

{

  unsigned int j;

  for(i;i>0;i--)

        for(j = 112; j >0; j--);

}

//----------------------------------------------

void display()                    //display

{

  	duan=tab[ge];

wei1=0;

wei2=0;

wei3=0;

wei4=1;

delay(5);

duan=tab[shi];

wei1=0;

wei2=0;

wei3=1;

wei4=0;

delay(5);

duan=tab[bai];

wei1=0;

wei2=1;

wei3=0;

wei4=0;

delay(5);

duan=tab[qian];

wei1=1;

wei2=0;

wei3=0;

wei4=0;

delay(5);

}

//----------------------------------------------

void main (void)

{

    SCON = 0x50;  

    TMOD = 0x20; 

    TH1 = 0xFD; 

    TL1 = 0xFD;

    TR1 = 1;                        

    ES= 1;     //port interrupt

EA=1;      //sum interrupt



    EX0=1;	   //out interrupt 0

    IT0=1;	   //1-down edge ,0-low 

PX0=1;     //First



    EX1=1;	   //out interrupt 1

    IT1=1;	   //1-down edge ,0-low 

PX1=0;     //second



    while(1)  

 { 

display();	

      if ((New_rec == 1) && (Send_ed == 1))  

{  	

New_rec = 0;

Send_ed = 0;

        }

      }

}



//----------------------------------------------

void int0() interrupt 0    //sensor1 interrupt

{

 LED1=~LED1;

//   num1++;

// //sprintf(SEND_buff,"%8d",num1,"\n");

// printf(SEND_buff,"%s : %s",num1,num2);

//   ge=num1%10;

//   shi=num1/10%10;

//   bai=num2%10;

//   qian=num2/10%10;

//   if(num1==99)

//   num1=0;

}



//----------------------------------------------

void int1() interrupt 1    //sensor2 interrupt

{

    LED2=~LED2;

//   num2++;

// //sprintf(SEND_buff,"%8d",num2,"\n");

// printf(SEND_buff,"%s : %s",num1,num2);

//   ge=num1%10;

//   shi=num1/10%10;

//   bai=num2%10;

//   qian=num2/10%10;

//   if(num2==99)

//   num2=0;

}

//----------------------------------------------

void ser_int (void) interrupt 4    //serial port

{

    if(RI == 1) 

{ 

      RI = 0;              //recive string

      New_rec = 1;

      UART_buff = SBUF; 

      if(UART_buff == '#')

{ //LED = 1,num1=0,num2=0;

//sprintf(SEND_buff,"%8d",num1,"\n");

sprintf(SEND_buff,"%s : %s",num1,num2);

            }

else if(UART_buff == '$') 

{ //LED = 0;

SendString(SEND_buff);

}

else if(UART_buff == '%') 

{ //LED = 0;

SendString(SEND_buff);

     	}

      }

    else 

  { 

  SendString(SEND_buff);     //send string

      TI = 0;  

      Send_ed = 1;

    }

//delay(200);

  //while(P3^2==0);

} 

void SendChar(unsigned char Chr)

{	

SBUF=Chr;

while(!TI);

TI=0;

}

void SendString(unsigned char *p)

{

while(*p)

{

SendChar(*p);

p++;

}

}


修改了几个地方，为了快速测试，在PROTEUS上面仿真通过

xiaolongx 2017-08-31
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问题解决了一半，将 void int1() interrupt1    //sensor2 interrupt 改为 void int1() interrupt 2    //sensor2 interrupt 双中断计数可工作。 还有问题是如何将两个结果拼接成一窜字符输出？ 刚入手单片机，请教！
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