请问 各位大神 怎样将 json 存入数组？

[初学者的浅谈]

现在有一个json 需要存入 数组 jsonarry 怎样弄？

{
"data": [
{
"typeid": 2,
"txt": "人力资源",
"title": "",
"children": [
{
"nameid": 6,
"txt": "入职手续",
"code": "crylbx",
"title": "身份证、正反面等入职"
},{
"nameid": 7,
"txt": "社保接入",
"code": "crylbx",
"title": "社保卡号、社保密码社保接入"
}
]
}, {
"typeid": 1,
"txt": "计划生育",
"title": "",
"children": [
{
"nameid": 1,
"txt": "准生证",
"code": "zsz",
"title": "准生证准备材料"
}, {
"nameid": 2,
"txt": "独生子女证",
"code": "dszn",
"title": "独生子女证 准备材料"
}, {
"nameid": 3,
"txt": "计划生育证",
"code": "jhsy",
"title": "计划生育证 准备材料\r\n1、材料1\r\n2、材料3\r\n3、材料3"
}
]
}
]
}
上边是 json


下边这个怎么写 或者 哪位大神 有更好的方法
var jsonarry=[ ];
$.each(data.data, function(i, item) {
jsonarry.push({
//将json 追加入数组
name: this.name,
txt: this.txt,
children: 这里怎么写
});

});

[Go 旅城通票]

javascript树数据源嵌套结构和扁平结构互转

[转身后_从未想过离开你]

如果只单纯的把json装入数组的话，如下可以实现。 let jsonData = { "data": [ { "typeid": 2, "txt": "人力资源", "title": "", "children": [ { "nameid": 6, "txt": "入职手续", "code": "crylbx", "title": "身份证、正反面等入职" },{ "nameid": 7, "txt": "社保接入", "code": "crylbx", "title": "社保卡号、社保密码社保接入" } ] },  { "typeid": 1, "txt": "计划生育", "title": "", "children": [ { "nameid": 1, "txt": "准生证", "code": "zsz", "title": "准生证准备材料" }, { "nameid": 2, "txt": "独生子女证", "code": "dszn", "title": "独生子女证  准备材料" }, { "nameid": 3, "txt": "计划生育证", "code": "jhsy", "title": "计划生育证 准备材料\r\n1、材料1\r\n2、材料3\r\n3、材料3" } ] } ] }; let jsonArr=[ ]; for(let i in jsonData){ jsonArr.push({ i: jsonData[i] }) } console.log(jsonArr);

[初学者的浅谈]

我想不仅 要装入数组 而且格式一样

[x80819091]

ES6 let arr = Array.from(json)搞定

[clark_kidd]

<script>
var jsonarry = new Array();
var cArray = new Array();
cArray.push(new child("me", "test", []));
cArray.push(new child("you", "test2", []));

jsonarry.push({
name: "",
txt: "",
children: cArray
});

alert(jsonarry[0].children[0].name);
alert(jsonarry[0].children[1].name);

function child(name, txt, children){
	this.name = name;
	this.txt = txt;
	this.children = children;
}
</script>

[转身后_从未想过离开你]

var jsonData = {     "data": [         {         "typeid": 2,         "txt": "人力资源",         "title": "",         "children": [             {                 "nameid": 6,                 "txt": "入职手续",                 "code": "crylbx",                 "title": "身份证、正反面等入职"             },{                 "nameid": 7,                 "txt": "社保接入",                 "code": "crylbx",                 "title": "社保卡号、社保密码社保接入"             }         ]         },          {         "typeid": 1,         "txt": "计划生育",         "title": "",         "children": [             {                 "nameid": 1,                 "txt": "准生证",                 "code": "zsz",                 "title": "准生证准备材料"             }, {                 "nameid": 2,                 "txt": "独生子女证",                 "code": "dszn",                 "title": "独生子女证  准备材料"             }, {                 "nameid": 3,                 "txt": "计划生育证",                 "code": "jhsy",                 "title": "计划生育证 准备材料\r\n1、材料1\r\n2、材料3\r\n3、材料3"             }         ]         }     ] }; var jsonArr=[ ]; for(var i in jsonData.data){     jsonArr.push({         typeid: jsonData.data[i].typeid,//json里面没有name，故写了typeid txt: jsonData.data[i].txt, children: jsonData.data[i].children }); } console.log(jsonArr);

[x80819091]

这可能是代码最少的办法了

const { data } = obj
const arr = data.map(el => el)
console.log(arr)

结果

[ { typeid: 2,
    txt: '人力资源',
    title: '',
    children: [ [Object], [Object] ] },
  { typeid: 1,
    txt: '计划生育',
    title: '',
    children: [ [Object], [Object], [Object] ] } ]