shell中的if比较

[virusswb]

autoTaskFinish.sh查询数据库，有返回值

if [ "$rtn" -ge 1 ]; then
 echo "0"
 exit 0
else
 echo "1"
 exit 100
fi

下面的这个shell调用上面的shell

#!/bin/bash
vday=$1


while true;
do
  vexists=`sh /home/oracle/shell/new/autoTaskFinish.sh $1`
  echo $vexists
  if [ $vexists -eq 0 ]; then
    echo "autotask is finished."
  fi
#  if [[ "$vexists" -eq 0 ]]; then
#    echo "autotask is finished."
#    break
#  else
#    echo "autotask is not finished. continue....."
#    echo "sleep 5s"
#    sleep 2s
#  fi
done

运行的时候报错了，[: too many arguments
我修改为
if [[ $vexists -eq 0 ]]
还是报错syntax error in expression (error token is ":

改成
if [[ "$vexists" -eq 0 ]]
还是报错syntax error in expression (error token is ":

我修改为if [[ "$vexists" == "0" ]]; then
不会报错了，但是始终是不会进入这个if条件，不管之前的shell返回的是0还是1，也就是判断失效了，哪位帮忙解释一下！！！

[mymtom]

运行了，没有设么问题呀！