请教一个stm32+UCGUI动态显示图像的问题

闲着也是闲着552 2017-09-27 12:19:02

最近在用stm32f103vct6加UCGUI做一个涉及导航的项目，原理是通过蓝牙串口接收的数据显示导航状态图标（左转右转直行箭头什么的），所以编程的思路想用UCGUI的位图显示功能，把图标图像转换成C文件，然后通过对比数据加载不同图标，但是由于图标太多，编译总是通不过，提示溢出。代码简单呈现如下：

extern const GUI_BITMAP bmturn_back;
extern const GUI_BITMAP bmturn_branch_center;
extern const GUI_BITMAP bmturn_branch_left;
extern const GUI_BITMAP bmturn_branch_right;
//…………定义图像，很多，省略
extern const GUI_BITMAP bmturn_tollgate;

const int ShowIcon(char *str,int x,int y) {
GUI_BITMAP tt1;
int re = 0;
if (strcmp(str,"turn_back")) { tt1=bmturn_back; re = 1;};//对比串口传输数据，加载图像显示
if (strcmp(str,"turn_branch_center")) { tt1=bmturn_branch_center; re = 1; };
if (strcmp(str,"turn_branch_left")) { tt1=bmturn_branch_left; re = 1; };
if (strcmp(str,"turn_branch_right")) { tt1=bmturn_branch_right; re = 1; };
if (strcmp(str,"turn_branch_right_straight")){ tt1=bmturn_branch_right_straight; re = 1; };
if (strcmp(str,"turn_dest")) { tt1=bmturn_dest; re = 1; };
if (strcmp(str,"turn_front")) { tt1=bmturn_front; re = 1; };
if (strcmp(str,"turn_left_2branch_left")) { tt1=bmturn_left_2branch_left; re = 1; };
if (strcmp(str,"turn_left_2branch_right")) { tt1=bmturn_left_2branch_right; re = 1; };
if (strcmp(str,"turn_left_3branch_left")) { tt1=bmturn_left_3branch_left; re = 1; };
if (strcmp(str,"turn_left_3branch_middle")) { tt1=bmturn_left_3branch_middle; re = 1; };
if (strcmp(str,"turn_left_3branch_right")) { tt1=bmturn_left_3branch_right; re = 1; };
if (strcmp(str,"turn_left_back")) { tt1=bmturn_left_back; re = 1; };
if (strcmp(str,"turn_left_side")) {tt1=bmturn_left_side; re = 1};
if (strcmp(str,"turn_left_side_ic")) { tt1=bmturn_left_side_ic; re = 1;}
if (strcmp(str,"turn_left_side_main")) { tt1=bmturn_left_side_main; re = 1};
if (strcmp(str,"turn_right")) { tt1=bmturn_right; re = 1};
if (strcmp(str,"turn_right_2branch_left")) { tt1=bmturn_right_2branch_left; re = 1;}
if (strcmp(str,"turn_right_2branch_right")) { tt1=bmturn_right_2branch_right; re = 1;}
if (strcmp(str,"turn_right_3branch_left")) { tt1=bmturn_right_3branch_left; re = 1;}
if (strcmp(str,"turn_right_3branch_middle")) { tt1=bmturn_right_3branch_middle; re = 1;}
if (strcmp(str,"turn_right_3branch_right")) { tt1=bmturn_right_3branch_right; re = 1;}
if (strcmp(str,"turn_right_back")) { tt1=bmturn_right_back; re = 1;}
if (strcmp(str,"turn_right_front")) { tt1=bmturn_right_front; re = 1;}
if (strcmp(str,"turn_right_side")) { tt1=bmturn_right_side;}
if (strcmp(str,"turn_right_side_ic")) { tt1=bmturn_right_side_ic; re = 1;}
if (strcmp(str,"turn_right_side_main")) { tt1=bmturn_right_side_main; re = 1;}
if (strcmp(str,"turn_tollgate")) { tt1=bmturn_tollgate; re = 1;}
if (re==1) GUI_DrawBitmap(&tt1,x,y);
return re;
}

超过13个就会编译溢出，大量报错如下：
.\Output\Tiky_uCGUI_DEMO.axf: Error: L6406E: No space in execution regions with .ANY selector matching lcdinfo0.o(i.LCD_GetYSize).
请问这个问题如何解决？

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