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分享mysql问题$result的值为FASLE
echo $sql.'<br>';var_dump($db).'<br>';var_dump($result).'<br>';
$sql="SELECT RowID,code,ShopName,TotalRecord,ShippingFee,CreateDate,CreateOperator FROM t_kd_trackinghead where active_flag='1' ";$db = mysql_connect("127.0.0.1", "root","123456");
$sql="SELECT RowID,code,ShopName,TotalRecord,ShippingFee,CreateDate,CreateOperator FROM t_kd_trackinghead where active_flag='1' ";$db = mysql_connect("127.0.0.1", "root","123456");
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sm_xy1314 2017-11-11
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CREATE TABLE `t_kd_trackinghead` (
`RowID` int(11) NOT NULL ,
`Code` varchar(8) NOT NULL DEFAULT '' ,
`ShopName` varchar(30) NULL DEFAULT '' ,
`TotalRecord` int(11) NULL DEFAULT 0 ,
`ShippingFee` float NULL DEFAULT 0 ,
`CreateDate` varchar(20) NULL DEFAULT '' ,
`CreateOperator` varchar(30) NULL DEFAULT '' ,
`Active_Flag` char(1) NOT NULL DEFAULT 1 ,
PRIMARY KEY (`RowID`)
)
ENGINE=MyISAM
DEFAULT CHARACTER SET=utf8 COLLATE=utf8_bin
AUTO_INCREMENT=10000001
CHECKSUM=0
DELAY_KEY_WRITE=0
;强行怼出来的表格，问题在哪求指点
sm_xy1314 2017-11-11
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mysql 数组赋值_$data = array(); while ($row = mysql_fetch_array($result)) { $data[] = $row; }这个是什么意思呢...
