Point类的运算

[parhat2015]

定义Point类，有坐标x,y两个私有成员变量;对Point类重载“+”（相加）、“-”（相减）和“==”（相等）运算符，实现对坐标的改变，要求用友元函数和成员函数两种方法实现。对Point类重载<<运算符，以使得代码 Point p; cout<<p<<endl;可以输出该点对象的坐标。


/* 请在这里填写答案 */



int main(int argc, char const *argv[])
{
Point p1(2,3);
cout<<p1<<endl;
Point p2(4,5);
cout<<p2<<endl;
Point p3 = p1+p2;
cout<<p3<<endl;
p3 = p2-p1;
cout<<p3<<endl;
p1 += p2;
cout<<p1<<endl;
cout<<(p1==p2)<<endl;
return 0;
}

在这里给出相应的输出。例如：
2,3
4,5
6,8
2,2
6,8
0

[「已注销」]

自己填充一下代码就行了：

// member function style
class Point {
private:
	int _x;
	int _y;
public:
	Point();
	Point(int x, int y);
	const Point operator+(const Point &pt);
	const Point operator-(const Point &pt);
	const Point &operator+=(const Point &pt);
	const Point &operator-=(const Point &pt);
	bool operator==(const Point &pt) const;
	friend ostream &operator<<(ostream &out, const Point &pt);
};

// friend function style
class Point {
private:
	int _x;
	int _y;
public:
	Point();
	Point(int x, int y);
	friend const Point operator+(const Point &pt1, const Point &pt2);
	friend const Point operator-(const Point &pt1, const Point &pt2);
	friend const Point &operator+=(Point &pt1, const Point &pt2);
	friend const Point &operator-=(Point &pt1, const Point &pt2);
	friend bool operator==(const Point &pt1, const Point &pt2);
	friend ostream &operator<<(ostream &out, const Point &pt);
};

[真相重于对错]

这种题目还是自己做比较好