php 无法将获取的json数据转换成数组,结果是 null

[q|0_0|p]

我有一问题请教各位高手：我在获取的json数据无法转换成数组！我尝试了网上的几种方法结果都失败。结果是 null
现在我将问题呈上：
短短几行代码却耗费了几小时还是不能解决.

        $url   = 'http://home.flashdata2.jrj.com.cn/limitStatistic/dtForce/20190724.js';
        $check = file_get_contents($url);

        $result = '{"test":[' . trim(trim(substr($check, strripos($check, "Data") + 7), ']};')) . ']}';
        echo $result;
        var_dump(json_decode($result, true));exit;

一、接口获取的数据并非标准的json格式，我将其进行的并接。
原始数据

var yzb_dtForce={"summary":{size:1,time:"2019-07-24 15:59:55"}, "column":{stockcode:0,stockname:1,nowPrice:2,priceLimit:3,fcb:4,flb:5,fdMoney:6,firstZtTime:7,lastZtTime:8,opentime:9,zhenfu:10,force : 11}, "Data":[["600485","*ST新海",9.2,-4.96,5182.805,0.18929227,3.15653555E9,"09:25:04","09:25:04",0,0.0,100.0] ]};

输出的数据

{"test":[["600485","*ST 新海",9.2,-4.96,5182.805,0.18929227,3.15653555E9,"09:25:04","09:25:04",0,0.0,100.0]]}

二、用我拼接好的数据请求是可以正常 json 转成数组.

$check = file_get_contents('php://input');
        var_dump(json_decode($check, true));exit;

array (size=1)
  'test' => 
    array (size=1)
      0 => 
        array (size=12)
          0 => string '600485' (length=6)
          1 => string '*ST 新海' (length=15)
          2 => float 9.2
          3 => float -4.96
          4 => float 5182.805
          5 => float 0.18929227
          6 => float 3156535550
          7 => string '09:25:04' (length=8)
          8 => string '09:25:04' (length=8)
          9 => int 0
          10 => float 0
          11 => float 100

希望高手帮助实现的目标
能将在php环境下,将获取的数据成功地转换成数组！
——期待高手们的帮助，如获解决，本人不胜感激！

[于小九]

//json数组操作必须为标准的UTF-8编码，经测试直接读取接口返回信息第二位为GB2312编码导致的json_encode返回false与json_decode返回null的问题，所以在操作前先转换一下为标准UTF-8格式即可正常操作。 <?php $url = 'http://home.flashdata2.jrj.com.cn/limitStatistic/dtForce/20190724.js'; $check = file_get_contents($url); echo $str = "{\"test\":[".mb_convert_encoding(substr($check, strripos($check, "Data") + 8,strripos($check, "] ]};") -6),"UTF-8","GB2312") . "]}"; var_dump(json_decode($str,true)); /* $str = mb_convert_encoding(substr($check, strripos($check, "Data") + 8,strripos($check, "] ]};") -6),"UTF-8","GB2312"); $arr = str_replace("\"","",explode(",",$str)); var_dump($arr); $arr2 = "{\"test\":".json_encode($arr)."}"; var_dump(json_decode($arr2,true)); */ //$arr = '{"test":["600485","*ST\ufffd\ufffd\ufffd\ufffd",9.1999999999999993,-4.96,5182.8050000000003,0.18929227000000001,3156535550,"09:25:04","09:25:04",0,0,100]}'; //var_dump(json_decode($arr,true));

[yt_php]

不知道你的需求，php中通过js文件取数据，没咋见过这么干的

[yt_php]

引用 2 楼 yt_php 的回复:

不知道你的需求，php中通过js文件取数据，没咋见过这么干的

一种办法，参考。

//location.php内容 跳转到test.php
<script src="http://home.flashdata2.jrj.com.cn/limitStatistic/dtForce/20190724.js"></script>
<script>
	var yzb_dtForce =  JSON.stringify(yzb_dtForce);
	console.log(yzb_dtForce);

	window.location.href="test.php?yzb_dtForce="+yzb_dtForce
</script>

//test.php 接收get参数
<?php
$yzb_dtForce = $_GET['yzb_dtForce'];
print_r( json_decode($yzb_dtForce,true));

//Array ( [summary] => Array ( [size] => 1 [time] => 2019-07-24 15:59:55 ) [column] => Array ( [stockcode] => 0 [stockname] => 1 [nowPrice] => 2 [priceLimit] => 3 [fcb] => 4 [flb] => 5 [fdMoney] => 6 [firstZtTime] => 7 [lastZtTime] => 8 [opentime] => 9 [zhenfu] => 10 [force] => 11 ) [Data] => Array ( [0] => Array ( [0] => 600485 [1] => *ST信威 [2] => 9.2 [3] => -4.96 [4] => 5182.805 [5] => 0.18929227 [6] => 3156535550 [7] => 09:25:04 [8] => 09:25:04 [9] => 0 [10] => 0 [11] => 100 ) ) )