c# 画图

RyanNewLife 2020-09-24 11:07:34

有个任务，有一堆点，每个点都有X值和Y值。其中X值比较大大概都在10000以上，每个点的X值波动比较小。Y值大概在100以内。现在要把这些点都描绘出来。我自己整了一下代码，由于X值都超出了窗口像素大小所以无法显示，我想请教下各位这种情况下该怎么写代码？我自己的代码贴出来了，需要怎么修改代码？麻烦各位了



            Graphics g = Graphics.FromHwnd(this.Handle);



            Pen p = new Pen(Color.Black);



            p.EndCap = LineCap.ArrowAnchor;



            g.DrawLine(p, new Point(100, this.Height - 100), new Point(this.Width - 100, this.Height - 100));



            g.DrawString("x", this.Font, new SolidBrush(Color.Black), new Point(this.Width - 100 + 5, this.Height - 100));



            p.EndCap = LineCap.ArrowAnchor;



            g.DrawLine(p, new Point(150, this.Height - 50), new Point(150, 100));



            g.DrawString("y", this.Font, new SolidBrush(Color.Black), new Point(150, 100 - 20));



            int pointCount = 2;



            float[] pointX = new float[] {12213.00f,11221.00f};



            float[] pointY = new float[] { 32.4f, 33.1f };

            

            PointF[] pointF = new PointF[pointCount];



            for (int i = 0; i < pointCount; i++) {



                pointF[i] = new PointF(pointX[i], pointY[i]);



            }



            g.DrawCurve(p, pointF, 1f);



            p.Dispose();



            g.Dispose();