初学者询问一个关于匿名类传值的问题，请各位前辈帮忙

其实我也恋长安 2020-10-26 05:30:55

public class People {



    public interface Runner {

        void run();

    }

    public void stuAge(int num){

        System.out.println("The age of the Student is"+num);

    }



    public static void main(String[] args) {

        Runner runner = new Runner() {

            @Override

            public void run1() {

                int age = 18;

                System.out.println("run 10 miles!");

            }

        };

        runner.run();



        People people = new People();

        people.stuAge(age);

    }

}

我想知道如何把匿名内部类的age传到外面stuAge中，请各位前辈帮忙看看

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qybao 2020-10-27

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用个list保存结果就可以了
for example



public class People {

     

    public static interface Runner {

        void run();

    }

    public void stuAge(int num){

        System.out.println("The age of the Student is"+num);

    }

 

    public static void main(String[] args) {

        List<Integer> list = new ArrayList<>(); //用于保存内部类的结果

        Runner runner = new Runner() {

            @Override

            public void run() {

                int age = 18;

                list.add(age); //保存内部类处理结果

                System.out.println("run 10 miles!");

            }

        };

        runner.run();

 

        People people = new People();

        people.stuAge(list.get(0)); //使用保存的结果

    }

}

KeepSayingNo 2020-10-27

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public class People {
    private Integer age;
    public interface Runner {
        void run();
    }
    public void stuAge(int num){
        System.out.println("The age of the Student is"+num);
    }
 
    public static void main(String[] args) {
        Runner runner = new Runner() {
            @Override
            public void run1() {
                this.setAge(18);
                System.out.println("run 10 miles!");
            }
        };
        runner.run();
    }

    public Integer getAge() {
        return age;
    }

    public void setAge(Integer age) {
        this.age = age;
    }
}

其实我也恋长安 2020-10-27

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引用 6 楼 qq_39936465 的回复:

[quote=引用 1 楼其实我也恋长安的回复:]

/**
 * @description: 匿名内部类
 * @author:
 * @date: 2020/10/26 9:47
 */
public class People {

    public interface Runner1 {
        void run1();
        int run2();
    }

    public void stuAge(int num){
        System.out.println("The age of the Student is " + num);
    }

    public static void main(String[] args) {
        Runner1 runner = new Runner1() {
            int age;
            @Override
            public void run1() {
                age = 18;
                System.out.println("run 10 miles!");
            }

            @Override
            public int run2() {
                return age;
            }
        };
        runner.run1();

        People people = new People();
        people.stuAge(runner.run2());
    }
}

除了使用这个办法，还有其他办法吗？假如接口是无法修改的情况下


public class People {
	 
	int age;
	
    public interface Runner {
        void run();
    }
    public void stuAge(int num){
        System.out.println("The age of the Student is"+num);
    }
 
    public static void main(String[] args) {
    	People people = new People();
        Runner runner = new Runner() {
            @Override
            public void run() {
                people.setAge(18);
                System.out.println("run 10 miles!");
            }
			
        };
        runner.run();
 
        people.stuAge(people.getAge());
    }
    public int getAge() {
		return age;
	}
	public void setAge(int age) {
		this.age = age;
	}
}

[/quote]谢谢，你这个补足了1楼的答案。

qq_39936465 2020-10-27

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引用 1 楼其实我也恋长安的回复:

/**
 * @description: 匿名内部类
 * @author:
 * @date: 2020/10/26 9:47
 */
public class People {

    public interface Runner1 {
        void run1();
        int run2();
    }

    public void stuAge(int num){
        System.out.println("The age of the Student is " + num);
    }

    public static void main(String[] args) {
        Runner1 runner = new Runner1() {
            int age;
            @Override
            public void run1() {
                age = 18;
                System.out.println("run 10 miles!");
            }

            @Override
            public int run2() {
                return age;
            }
        };
        runner.run1();

        People people = new People();
        people.stuAge(runner.run2());
    }
}

除了使用这个办法，还有其他办法吗？假如接口是无法修改的情况下


public class People {
	 
	int age;
	
    public interface Runner {
        void run();
    }
    public void stuAge(int num){
        System.out.println("The age of the Student is"+num);
    }
 
    public static void main(String[] args) {
    	People people = new People();
        Runner runner = new Runner() {
            @Override
            public void run() {
                people.setAge(18);
                System.out.println("run 10 miles!");
            }
			
        };
        runner.run();
 
        people.stuAge(people.getAge());
    }
    public int getAge() {
		return age;
	}
	public void setAge(int age) {
		this.age = age;
	}
}

其实我也恋长安 2020-10-27

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引用 3 楼 qybao 的回复:

用个list保存结果就可以了 for example


public class People {
     
    public static interface Runner {
        void run();
    }
    public void stuAge(int num){
        System.out.println("The age of the Student is"+num);
    }
 
    public static void main(String[] args) {
        List<Integer> list = new ArrayList<>(); //用于保存内部类的结果
        Runner runner = new Runner() {
            @Override
            public void run() {
                int age = 18;
                list.add(age); //保存内部类处理结果
                System.out.println("run 10 miles!");
            }
        };
        runner.run();
 
        People people = new People();
        people.stuAge(list.get(0)); //使用保存的结果
    }
}

这个可以，谢谢。

其实我也恋长安 2020-10-27

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引用 2 楼 KeepSayingNo 的回复:


public class People {
    private Integer age;
    public interface Runner {
        void run();
    }
    public void stuAge(int num){
        System.out.println("The age of the Student is"+num);
    }
 
    public static void main(String[] args) {
        Runner runner = new Runner() {
            @Override
            public void run1() {
                this.setAge(18);
                System.out.println("run 10 miles!");
            }
        };
        runner.run();
    }

    public Integer getAge() {
        return age;
    }

    public void setAge(Integer age) {
        this.age = age;
    }
}

这个不行，this.setAge(18);报错

其实我也恋长安 2020-10-26

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/**
 * @description: 匿名内部类
 * @author:
 * @date: 2020/10/26 9:47
 */
public class People {

    public interface Runner1 {
        void run1();
        int run2();
    }

    public void stuAge(int num){
        System.out.println("The age of the Student is " + num);
    }

    public static void main(String[] args) {
        Runner1 runner = new Runner1() {
            int age;
            @Override
            public void run1() {
                age = 18;
                System.out.println("run 10 miles!");
            }

            @Override
            public int run2() {
                return age;
            }
        };
        runner.run1();

        People people = new People();
        people.stuAge(runner.run2());
    }
}

除了使用这个办法，还有其他办法吗？假如接口是无法修改的情况下