还是xslt的问题

[jwwu]

一个mxl文档如下
<?xml version="1.0" encoding="GB2312"?>
<A>
<a>
<name>...</name>
</>
<a>
<name>...</name>
</a>
<a>
<name>...</name>
</>
<a>
<name>...</name>
</a>
...
</A>
元素<a>还有很多
我想position() = 1 和 position() = 2是一种处理样式 position() = 3 和 position() = 4又是一种处理样式，然后循环10次 ，请问我怎么写这个xsl

[zhfkiller]

用css

[孟子E章]

http://xml.sz.luohuedu.net/xml/ShowList.asp?id=11

[ssm1226]

<?xml version="1.0" encoding="UTF-8"?>
<?xml-stylesheet type="text/xsl" href="csdn0047.xsl"?>
<A>
<a>
<name>ssm1226-1</name>
</a>
<a>
<name>ssm1226-2</name>
</a>
<a>
<name>ssm1226-3</name>
</a>
<a>
<name>ssm1226-4</name>
</a>
<a>
<name>ssm1226-5</name>
</a>
<a>
<name>ssm1226-6</name>
</a>
<a>
<name>ssm1226-7</name>
</a>
<a>
<name>ssm1226-8</name>
</a>
<a>
<name>ssm1226-9</name>
</a>
</A>

csdn0047.xsl
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="/">
<style type="text/css">
.tr1{background-color:red}
.tr2{background-color:blue}
</style>
<table border="1">
<xsl:for-each select="A/a">
<xsl:variable name="pos" select="position()"/>
<xsl:if test="$pos mod 2=1 and $pos < 20 ">
<tr>
<xsl:choose>
<xsl:when test="($pos+1) mod 4 =0">
<xsl:attribute name="class">tr2</xsl:attribute>
</xsl:when>
<xsl:when test="($pos+1) mod 2 =0">
<xsl:attribute name="class">tr1</xsl:attribute>
</xsl:when>
</xsl:choose>

<td><xsl:value-of select="$pos"/></td>
<td><xsl:value-of select="name"/></td>
</tr>
<xsl:if test="following-sibling::a[1]">
<tr>
<xsl:choose>
<xsl:when test="($pos+1) mod 4 =0">
<xsl:attribute name="class">tr2</xsl:attribute>
</xsl:when>
<xsl:when test="($pos+1) mod 2 =0">
<xsl:attribute name="class">tr1</xsl:attribute>
</xsl:when>
</xsl:choose>
<td><xsl:value-of select="$pos + 1"/></td>
<td><xsl:value-of select="following-sibling::a[1]/name"/></td>
</tr>
</xsl:if>
</xsl:if>
</xsl:for-each>
</table>
</xsl:template>
</xsl:stylesheet>