String two,sixteen,eight //定义三个字符串变量,用来存放最后输出的进制值
String ls_return
Long lentwo,duan,i,j
String aa[50],a[50],b[4]
//====================================================================
// 先把10进制数据通过取余数转换成2进制
// 10进制到2进制的转换是通过取余数实现
//====================================================================
DO WHILE ai_value > 0
two = two + String(Mod(ai_value,2))
ai_value = ai_value / 2
LOOP
//====================================================================
// 选择输出进制
//====================================================================
CHOOSE CASE ai_how
CASE 2
//由于上面得到的2进制的数据方向是相反的:11011101101,所以要通过reverse()函数重新//把它颠倒过来
two = Reverse(two) //得到正确的2进制10110111011
ls_return= two
CASE 8
//2进制到8进制的转换是这样的,从右往左每3位为一个段,即8进制的一位,
lentwo = Len(two) //取2进制的长度
IF Mod(lentwo,3) > 0 THEN //分段
duan = lentwo / 3 + 1
ELSE
duan = lentwo /3
END IF
FOR i = duan TO 1 STEP -1 //由于没有颠倒过来的2进制是从右往左的,所以//分出来的段从左往右就是由大到小
aa[duan] = Mid(two,i * 3 - 2 ,3) //取出每一段的2进制值
a[duan] = '0'
FOR j = 1 TO 3
b[j] = Mid(aa[duan],j,1) //每一段从右往左取值
IF b[j] <> '' THEN
a[duan] = String(Integer(a[duan]) + 2^(j -1 ) * Integer(b[j]))
//按照2^0 * x + 2^1 *x +2^2 * x
//x为分别为从右到左的2进制的值,累加得到每一段的8进制值
END IF
NEXT
eight = eight + a[duan] //8进制段累加得到最后的8进制值
NEXT
ls_return= eight
CASE 16
//16进制的方法如同8进制,只是每4位为一段而已
lentwo = Len(two)
IF Mod(lentwo,4) > 0 THEN
duan = lentwo / 4 + 1
ELSE
duan = lentwo /4
END IF
FOR i = duan TO 1 STEP -1
aa[duan] = Mid(two,i * 4 - 3 ,4)
a[duan] = '0'
FOR j = 1 TO 4
b[j] = Mid(aa[duan],j,1)
IF b[j] <> '' THEN
a[duan] = String(Integer(a[duan]) + 2^(j -1 ) * Integer(b[j]))
END IF
CHOOSE CASE Integer(a[duan])
CASE 10
a[duan] = 'A'
CASE 11
a[duan] = 'B'
CASE 12
a[duan] = 'C'
CASE 13
a[duan] = 'D'
CASE 14
a[duan] = 'E'
CASE 15
a[duan] = 'F'
END CHOOSE
NEXT
sixteen = sixteen + a[duan]
NEXT
ls_return= sixteen
CASE ELSE
END CHOOSE