Dim strReturn,i,ThisCharCode,innerCode,Hight8,Low8,NextCharCode
strReturn = ""
For i = 1 To LenB(vIn)
ThisCharCode = AscB(MidB(vIn,i,1))
If ThisCharCode < &H80 Then
strReturn = strReturn & Chr(ThisCharCode)
Else
NextCharCode = AscB(MidB(vIn,i+1,1))
strReturn = strReturn & Chr(CLng(ThisCharCode) * &H100 + CInt(NextCharCode))
i = i + 1
End If
Next
bytes2BSTR = strReturn
End Function
</script>
<script language="JavaScript">
function getXML(URL) {
var xmlhttp = new ActiveXObject("Microsoft.XMLHTTP");
xmlhttp.Open("GET",URL, false);
try {
xmlhttp.Send();
var result = xmlhttp.status;
}
catch(e) {
return(false);
}
if(result==200) {
return(bytes2BSTR(xmlhttp.responseBody));
}
var xmlhttp = null;
}
function update()
{
//alert("页面开始更新");
document.body.innerHTML = getXML('score2.asp'+'?tem='+Math.random());
}
setInterval("update()",1000)
</script>
</head>
<body>
</body>
</html>
以前提问时别人回复我的,看看你是不是适用!