textBox中输入的数字怎么转为float?

[syp133]

简单的问题；
另外怎么判断textBox中输入的是合法的数字而不是其他；

菜鸟的说；
今晚结贴；

[rgbcn]

private void TextBox_Validation(object sender,CancelEventArgs ce)
{
try
{
int value=Int32.Parse(this.Text);
}
catch(Exception)
{
ce.Cancel=true;
MessageBox.Show("Please Enter Numeric Value");
}
}

[孟子E章]

System.Single.Parse(TextBoxId.Text);
System.Decimal.Parse(TextBoxId.Text);

[rgbcn]

// Source Code starts

using System;
using System.Windows.Forms;
using System.ComponentModel;
using System.Drawing;

class NumberBox:TextBox
{
public NumberBox()
{
this.KeyPress+=new KeyPressEventHandler(NumberBox_KeyPress);
}

private void NumberBox_KeyPress(object sender,KeyPressEventArgs kpe)
{
int KeyCode=(int)kpe.KeyChar;

if(!IsNumberInRange(KeyCode,48,57) && KeyCode!=8 && KeyCode!=46)
{
kpe.Handled=true;
}
else
{
if(KeyCode==46)
{
kpe.Handled=(this.Text.IndexOf(".")>-1);
}
}
}

private bool IsNumberInRange(int Val,int Min,int Max)
{
return (Val>=Min && Val<=Max);
}
}

class NumberBoxDemo:Form
{
Label l1=new Label();
NumberBox n1=new NumberBox();
public NumberBoxDemo()
{
l1.Text="Number Box:";
n1.Location=new Point(l1.Left+l1.Width+10,l1.Top);
this.Controls.Add(l1);
this.Controls.Add(n1);
}

public static void Main()
{
Application.Run(new NumberBoxDemo());
}
}
// Source Code End

[JB-Zhang]

使用用类Convert的一个静态方法就可以了,Convert.ToFloat(),或 Convert.ToDouble()

[syp133]

谢谢各位了