高手过来一叙！

[zhlgsq]

//---------------------------------------------------------
class Point
{
int x,y;
public:
int GetPointx(){return x;}
int GetPointy(){return y;}
Point(int set_x,int set_y);
void ShowPoint(void);
};

void Point::ShowPoint(void)
{
cout<<"\nx="<<x;
cout<<"\ny="<<y;

}

Point::Point(int set_x,int set_y)
{
x=set_x;

y=set_y;

}

//-----------------------------------------------------------------

class Circle:public Point
{
int radius;
int cx,xy;
public:

void ShowCircle(void)
{
cout<<"x="<<GetPointx();
cout<<"y="<<GetPointy();
cout<<"Radius"<<radius;
}
Circle();

Circle(int cx,int cy,int rad):Point(int cx,int cy),radius(rad)
{}

}

请问：Circle(int cx,int cy,int rad):Point(int cx,int xy),radius(rad){}
问题出在哪里？如何改？

[Jinhao]

Circle(int cx,int cy,int rad):Point(cx,xy),radius(rad){}

[zhlgsq]

此句如果改成:Circle(int cx,int xy,int rad):GetPointx(),GetPointy(),radius(rad){}
如何?

[minghui000]

这题目都要需要高手来？

[Jinhao]

Circle(int cx,int xy,int rad):[GetPointx(),GetPointy(),radius(rad)]{}

被[]括起来的部分是初始化表
例如
Circle(int cx,int cy,int rad):Point(cx,xy),radius(rad){}
Point(cx,xy):初始化Circle对象的的基类Point部分，调用的是构造函数(一个特殊函数)
radius(rad):初始化Circle对象的成员数据radius

而GetPointx(),GetPointy()，是两个普通函数，他们谁也不初始化