求一个简单函数!在线等

[ajsword]

读取一个文件,文件内容是十六进制的,如:01 23 ac 44
怎样读出这些数据,并按放到一个字符串数组a中
最后a的格式为a[][]={"01","23ac","44"}

[elife]

23 ac -> 23ac???
fscanf(stream, "%s", a[i]);

[ajsword]

对亚,是23 ac->23ac
其实只要读出{"01","23","ac","44"}的格式也可以

[elife]

fscanf(stream, "%s", a[i]);
就是实现读出{"01","23","ac","44"}的格式

[wildhorseych]

#include <iostream.h>

int ReadFile(const char *filename,char *pFile,int & nLen)
{
FILE *stream=NULL;
char buf[100];
int count=0;

if(pFile==NULL)
{
nLen=0;
stream=fopen(filename,"r");
if(stream==NULL)
{
perror("Open client.conf fail");
exit(-1);
}
while(!feof(stream))
{
count=fread(buf,sizeof(char),100,stream);
nLen+=count;
}
fclose(stream);
return 0;
}
stream=fopen(filename,"r");
fread(pFile,sizeof(char),nLen,stream);
fclose(stream);
return 0;
}

[ajsword]

fscanf是用来写的吧

[ajsword]

如果想把01 0d 3a读成一个整数形式0x010d3a要怎么办