高手求助！！！！！！！！！！！！1

[longer84]

2007-01-22 11:11:57,968 [com.ascent.dao.hibernate.CustomerHibernateDAO]-[DEBUG] 根据用户姓名得到用户信息！
Hibernate: select customer0_.customer_id as customer1_, customer0_.cust_name as cust_name, customer0_.password as password, customer0_.email as email from customer customer0_ where (customer0_.cust_name=? ) order by customer0_.customer_id desc
2007-01-22 11:11:58,203 [net.sf.hibernate.util.JDBCExceptionReporter]-[WARN] SQL Error: 0, SQLState: S0022
2007-01-22 11:11:58,203 [net.sf.hibernate.util.JDBCExceptionReporter]-[ERROR] Column 'customer1_' not found.
2007-01-22 11:11:58,218 [net.sf.hibernate.util.JDBCExceptionReporter]-[WARN] SQL Error: 0, SQLState: S0022
2007-01-22 11:11:58,218 [net.sf.hibernate.util.JDBCExceptionReporter]-[ERROR] Column 'customer1_' not found.
2007-01-22 11:11:58,218 [com.ascent.dao.hibernate.CustomerHibernateDAO]-[ERROR] 根据用户姓名获取用户信息失败！
org.springframework.jdbc.BadSqlGrammarException: Bad SQL grammar [] in task 'Hibernate operation'; nested exception is java.sql.SQLException: Column 'customer1_' not found.
java.sql.SQLException: Column 'customer1_' not found.


哪位能看一下这是什么问题！配置文件都没问题！就是跑不过去！检查又检查！。。。。。。。

[longer84]

表结构一样的啊！

[longer84]

郁闷ing.................

[imA]

你的hibernate配置跟你的数据库表结构不一样，在你要操作的表中没有customer1_这个字段。

[longer84]

自个顶一下呢！