正则取内容(很简单的)

2007-02-07 05:24:42 312 阅读 AI 写同款 · GEO 优化AI 选题数据监测一键分发 ›

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力扣：找到字符串中所有字母异位词题目描述给定一个字符串 s 和一个非空字符串 p，找到 s 中所有是 p 的字母异位词的子串，返回这些子串的起始索引。字符串只包含小写英文字母，并且字符串 s 和 p 的长度都不超过 20100。说明：字母异位词指字母相同，但排列不同的字符串。不考虑答案输出的顺序。力扣：438. 找到字符串中所有字母异位词输入 s : “cbaebabacd” p : “abc” 输出 [ 0 , 6 ] 解释: 起始索引等于 0 的子串是 “cba”, 它是 “abc” 的字母异位词。起始索阅读详情

内容:

string aa="Who Sub: aa.bb.cc sdlfjdslfjdsfldsjflsdjf...";

取出以下结果(要用正则实现,注意:是Who Sub:到第一个 之间的内容,":"后面有没有空格不确定)

aa.bb.cc

说一下我用以下的怎么不能取出:
Match m=Regex.Match(aa,"Who Sub:(.*)?[^ ]");
Match m=Regex.Match(aa,"(?<=Who Sub:)[\\w\\.]+[^ ]");
Console.Write(m.Groups[1].ToString());

...全文

通讯接口应用笔记3：使用W5500实现Modbus TCP服务器前面我们设计实现了W5500的驱动程序，也讲解了驱动的使用方式。在最近一次的项目应用中，正好有一个使用W5500实现TCP通讯的需求，所以我们就使用该驱动程序轻松实现。这一篇中我们就来说一说基于我们W5500通讯驱动程序实现TCP通讯的过程。 1、应用需求在本次应用中，要求实现一个基于W5500的Modbus TCP服务器。这个需求的描述虽然只有一句话，但是这个需求的内容可不简单。我们首先来分析一下这个需求的具体内容。为了实现基于W5500的Modbus TCP服务器，我们必先须基于W550 阅读详情

hq2008

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xiajian19820809 2007-02-07

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介绍三个C#技术群:
C#程序员在长沙1 群号:15283069
C#程序员在长沙2 群号:8689365
C#程序员在长沙3 群号:15082848

hq2008 2007-02-07

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就是取出下面的的"Whois Server: whois.networksolutions.com"中的whois.networksolutions.com

" Whois Server Version 1.3 Domain names in the .com and .net domains can now be registered with many different competing registrars. Go to http://www.internic.net for detailed information. Domain Name: SOHU.COM Registrar: NETWORK SOLUTIONS, LLC. Whois Server: whois.networksolutions.com Referral URL: http://www.networksolutions.com Name Server: NS3.SOHU.COM Name Server: NS1.SOHU.COM Name Server: NS2.SOHU.COM Status: clientTransferProhibited Updated Date: 31-jan-2007 Creation Date: 05-jul-1998 Expiration Date: 04-jul-2009 >>> Last update of whois database: Tue, 6 Feb 2007 16:00:38 EST <<< NOTICE: The expiration date displayed in this record is the date the registrar's sponsorship of the domain name registration in the registry is currently set to expire. This date does not necessarily reflect the expiration date of the domain name registrant's agreement with the sponsoring registrar. Users may consult the sponsoring registrar's Whois database to view the registrar's reported date of expiration for this registration. TERMS OF USE: You are not authorized to access or query our Whois database through the use of electronic processes that are high-volume and automated except as reasonably necessary to register domain names or modify existing registrations; the Data in VeriSign Global Registry Services' (\"VeriSign\") Whois database is provided by VeriSign for information purposes only, and to assist persons in obtaining information about or related to a domain name registration record. VeriSign does not guarantee its accuracy. By submitting a Whois query, you agree to abide by the following terms of use: You agree that you may use this Data only for lawful purposes and that under no circumstances will you use this Data to: (1) allow, enable, or otherwise support the transmission of mass unsolicited, commercial advertising or solicitations via e-mail, telephone, or facsimile; or (2) enable high volume, automated, electronic processes that apply to VeriSign (or its computer systems). The compilation, repackaging, dissemination or other use of this Data is expressly prohibited without the prior written consent of VeriSign. You agree not to use electronic processes that are automated and high-volume to access or query the Whois database except as reasonably necessary to register domain names or modify existing registrations. VeriSign reserves the right to restrict your access to the Whois database in its sole discretion to ensure operational stability. VeriSign may restrict or terminate your access to the Whois database for failure to abide by these terms of use. VeriSign reserves the right to modify these terms at any time. The Registry database contains ONLY .COM, .NET, .EDU domains and Registrars. "

hq2008 2007-02-07

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Who Sub:(?<test>.+) 与我Match m=Regex.Match(aa,"Who Sub:(.*)?[^ ]");这个不是一样的结果吗?我要的是只取出Who Sub:到第一个 之间的内容,第二个 第三个 是不要的,以上的会取出所有的 的,那这个问题就没有什么啦

hq2008 2007-02-07

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又碰到啦,cpp2017(慕白兄)你有没有测试,好像不行

cpp2017 2007-02-07

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string aa = "Who Sub: aa.bb.cc sdlfjdslfjdsfldsjflsdjf..."; Regex reg = new Regex(@"^Who Sub:([\s\S]*?) "); MatchCollection ms = reg.Matches(aa); if (ms.Count > 0) { Response.Write(ms[0].Result("$1")); }

laodeng72586 2007-02-07

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Who Sub:(?<test>.+)

正则取内容(很简单的)

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