1.4w+
社区成员
25.3w+
社区内容
- 主页
- 基础类
- 应用实例
- 新技术前沿
用Group后的合计
原来是这样的
select count(a) as aa,b from # group by b
现在要添加一行，aa的合计
select count(a) as aa,b from # group by b
现在要添加一行，aa的合计
...全文
Debug_mq 2007年03月15日
我和梅一样，
dawugui 2007年03月15日
select isnull(b,'合计') as b , count(a) as aa from # group by b with rollup
paoluo 2007年03月15日
Create Table TEST
(b Int,
a DateTime)
Insert TEST Select 1, '2007-01-03'
Union All Select 1, '2007-01-08'
Union All Select 2, '2007-01-06'
Union All Select 3, '2007-01-03'
Union All Select 3, '2007-02-03'
Union All Select 3, '2007-03-03'
GO
Select COUNT(a) As aa, b From TEST Group By b With Rollup
GO
Drop Table TEST
--Result
/*
aa b
2 1
1 2
3 3
6 NULL
*/
(b Int,
a DateTime)
Insert TEST Select 1, '2007-01-03'
Union All Select 1, '2007-01-08'
Union All Select 2, '2007-01-06'
Union All Select 3, '2007-01-03'
Union All Select 3, '2007-02-03'
Union All Select 3, '2007-03-03'
GO
Select COUNT(a) As aa, b From TEST Group By b With Rollup
GO
Drop Table TEST
--Result
/*
aa b
2 1
1 2
3 3
6 NULL
*/
paoluo 2007年03月15日
try
select count(a) as aa,b from # group by b with rollup
select count(a) as aa,b from # group by b with rollup
jacobsan 2007年03月15日
select count(aa) from (select count(a) as aa,b from # group by b) t group by aa
中国风 2007年03月15日
select count(a) as aa,count(1) as '合计',b from # group by b