怎么用正则来提取内容？马上给分

[silverseven7]

怎么用正则来提取内容？马上给分

String str = “ffafd&#test1;afafdi&#test2;&#test3;1344343....”

怎么把test1 ，test2，test3 （就是&#和;之间的内容？）给提取出来，然后放到数组里面啊？

[guanwl]

mark

[不想低调]

帮顶

[rlqiang]

http://www.ccw.com.cn/htm/app/aprog/01_7_31_4.asp

[rlqiang]

http://edu.yesky.com/edupxpt/115/2146615.shtml

[imA]

public class RegTest
{
/**
* @param args
*/
public static void main(String[] args)
{
java.util.regex.Pattern p=java.util.regex.Pattern.compile("&#([^&]*);");
java.util.regex.Matcher m=p.matcher("ffafd&#test1;afafdi&#test2;&#test3;1344343");
java.util.List list=new java.util.ArrayList();
while(m.find())
{
System.out.println(m.group(1));
list.add(m.group(1));
}
String[] s=(String[])list.toArray();
}
}

[imA]

上面的打错了。

public class RegTest
{
/**
* @param args
*/
public static void main(String[] args)
{
java.util.regex.Pattern p=java.util.regex.Pattern.compile("&#([^&]*);");
java.util.regex.Matcher m=p.matcher("ffafd&#test1;afafdi&#test2;&#test3;1344343");
java.util.List list=new java.util.ArrayList();
while(m.find())
{
System.out.println(m.group(1));
list.add(m.group(1));
}
Object[] s=list.toArray();
for(int i=0;i<s.length;i++)
System.out.println(s[i]);
}
}

[Catsou55]

ArrayList list = new ArrayList();
String regBrk = "&#([^;]*);";
String origin = "ffafd&#test1;afafdi&#test2;&#test3;1344343....";
Pattern patternBrk = Pattern.compile(regBrk);
Matcher matcherBrk = patternBrk.matcher(origin);
while(matcherBrk.find()){
String gp = matcherBrk.group(1);
list.add(gp);
}
Object[] array = (Object[])list.toArray();