您知道如何从String 或StringBuffer 中戴取若干个英文“单词”吗？

2002-05-02 11:14:44 200 阅读 AI 写同款 · GEO 优化AI 选题数据监测一键分发 ›

String与StringBuffer类-文本加密程序下面的一段文本中的各个单词是用空格隔开的。请将文中的每个单词的字母顺序翻转后，重新拼接成一个字符串输出。 “This is a beautiful world” 变成： "sihT si a lufituaeb dlrow " public class Encryption{ public static void main(String[] args) { StringBuffer sb=new StringBuffer(); StringBuffer sbtemp=new Strin 阅读详情

本人发现国内许多英文网页都有同样的问题，当你动态戴取长篇文章的一部份内容时往往会把单词折成两半。这在外国网页中是很少见的。本人虽然已经编了一方法得到解决，但想寻求简便方法。你能告诉我吗？

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模块学习（一）——编码电机编码电机测速阅读详情

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skyyoung 2002-05-03

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java.text
Class BreakIterator
java.lang.Object
|
+--java.text.BreakIterator

All Implemented Interfaces:
Cloneable

--------------------------------------------------------------------------------

public abstract class BreakIterator
extends Object
implements Cloneable
The BreakIterator class implements methods for finding the location of boundaries in text. Instances of BreakIterator maintain a current position and scan over text returning the index of characters where boundaries occur. Internally, BreakIterator scans text using a CharacterIterator, and is thus able to scan text held by any object implementing that protocol. A StringCharacterIterator is used to scan String objects passed to setText.

You use the factory methods provided by this class to create instances of various types of break iterators. In particular, use getWordIterator, getLineIterator, getSentenceIterator, and getCharacterIterator to create BreakIterators that perform word, line, sentence, and character boundary analysis respectively. A single BreakIterator can work only on one unit (word, line, sentence, and so on). You must use a different iterator for each unit boundary analysis you wish to perform.

Line boundary analysis determines where a text string can be broken when line-wrapping. The mechanism correctly handles punctuation and hyphenated words.

Sentence boundary analysis allows selection with correct interpretation of periods within numbers and abbreviations, and trailing punctuation marks such as quotation marks and parentheses.

Word boundary analysis is used by search and replace functions, as well as within text editing applications that allow the user to select words with a double click. Word selection provides correct interpretation of punctuation marks within and following words. Characters that are not part of a word, such as symbols or punctuation marks, have word-breaks on both sides.

Character boundary analysis allows users to interact with characters as they expect to, for example, when moving the cursor through a text string. Character boundary analysis provides correct navigation of through character strings, regardless of how the character is stored. For example, an accented character might be stored as a base character and a diacritical mark. What users consider to be a character can differ between languages.

BreakIterator is intended for use with natural languages only. Do not use this class to tokenize a programming language.

Examples:

Creating and using text boundaries

public static void main(String args[]) {
if (args.length == 1) {
String stringToExamine = args[0];
//print each word in order
BreakIterator boundary = BreakIterator.getWordInstance();
boundary.setText(stringToExamine);
printEachForward(boundary, stringToExamine);
//print each sentence in reverse order
boundary = BreakIterator.getSentenceInstance(Locale.US);
boundary.setText(stringToExamine);
printEachBackward(boundary, stringToExamine);
printFirst(boundary, stringToExamine);
printLast(boundary, stringToExamine);
}
}

Print each element in order
public static void printEachForward(BreakIterator boundary, String source) {
int start = boundary.first();
for (int end = boundary.next();
end != BreakIterator.DONE;
start = end, end = boundary.next()) {
System.out.println(source.substring(start,end));
}
}

Print each element in reverse order
public static void printEachBackward(BreakIterator boundary, String source) {
int end = boundary.last();
for (int start = boundary.previous();
start != BreakIterator.DONE;
end = start, start = boundary.previous()) {
System.out.println(source.substring(start,end));
}
}

Print first element
public static void printFirst(BreakIterator boundary, String source) {
int start = boundary.first();
int end = boundary.next();
System.out.println(source.substring(start,end));
}

Print last element
public static void printLast(BreakIterator boundary, String source) {
int end = boundary.last();
int start = boundary.previous();
System.out.println(source.substring(start,end));
}

Print the element at a specified position
public static void printAt(BreakIterator boundary, int pos, String source) {
int end = boundary.following(pos);
int start = boundary.previous();
System.out.println(source.substring(start,end));
}

Find the next word
public static int nextWordStartAfter(int pos, String text) {
BreakIterator wb = BreakIterator.getWordInstance();
wb.setText(text);
int last = wb.following(pos);
int current = wb.next();
while (current != BreakIterator.DONE) {
for (int p = last; p < current; p++) {
if (Character.isLetter(text.charAt(p))
return last;
}
last = current;
current = wb.next();
}
return BreakIterator.DONE;
}

(The iterator returned by BreakIterator.getWordInstance() is unique in that the break positions it returns don't represent both the start and end of the thing being iterated over. That is, a sentence-break iterator returns breaks that each represent the end of one sentence and the beginning of the next. With the word-break iterator, the characters between two boundaries might be a word, or they might be the punctuation or whitespace between two words. The above code uses a simple heuristic to determine which boundary is the beginning of a word: If the characters between this boundary and the next boundary include at least one letter (this can be an alphabetical letter, a CJK ideograph, a Hangul syllable, a Kana character, etc.), then the text between this boundary and the next is a word; otherwise, it's the material between words.)

See Also:
CharacterIterator

---------------
shmilu@sina.com

leonzhao 2002-05-03

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一般的国外网站现在都是动态摘要的，不是仅仅取出前多少个字就完事的事情。所以如果你需要截取前多少个字的话随便怎么做都是可以的，不用太考虑性能的问题。

您知道如何从String 或StringBuffer 中戴取若干个英文“单词”吗？

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