将Unicode的hex string转换为一个Byte Array，大家有什么好方法？

[NothingRemained]

比如hexString:"2A3BF7" (是Unicode的）
Byte Array:b[3]
转换后: b[0] = 0x2A,b[1] = 0x3B,b[2] = 0xF7

我想了一段时间，是越来越糊涂，那位出一下招。。。。？

[liulianxi]

BYTE hexString[] = "2A3BF7";
BYTE b[3];
for(int i=0; i<3; i++)
b[i] = hexString[i];

[zxs218]

char hexString[] = "2A3BF7";
BYTE b[3];
char * pStop;

for(int i=0; i<3; i++)
b[i] = strtol(&(hexString[i*2]), &pStop, 16);

[zxs218]

纠正一下：

#include <stdlib.h>
#include <stdio.h>
#include <string.h>


int main(int argc, char* argv[])
{
char hexString[] = "2A3BF7";
unsigned char b[3];
char * pStop;
char temp[3];

temp[2] = 0;

for(int i=0; i<3; i++) {
strncpy(temp, &(hexString[i*2]), 2);
b[i] = (unsigned char)strtol(temp, &pStop, 16);
}
printf("b[0] = %d, b[1] = %d, b[2] = %d.", b[0], b[1], b[2]);

return 0;
}