一个问题问两次！200分等待高手！

2002-05-13 03:29:37 343 阅读 AI 写同款 · GEO 优化AI 选题数据监测一键分发 ›

下载了一大堆发送emial的源代码程序，没有一个成功发送了邮件。有一个特别不明白的地方：为什么没有地方让我输入登录用户名和密码？用户名可以认为隐含，但密码呢？还有服务器连接方面也总不正确。（有一个在单步方式可以连上，一执行就连不上）请教各位高手！

前一个问题：“有关发送email的源代码问题，请教各位高手！”

解决了在两个地方一起加分！

...全文

用VFP计算 CRC-16 Modbus 校验位 1. Modbus是一种串行通信协议，最初由Modicon（目前属于施耐德电气公司）于1979年开发2. Modbus协议是应用在Modicon产品上的，后来才被移植到其他产品上3. Modbus协议的通信接口可以有多种选择，如RS232、RS485、以太网等。阅读详情

wjlcq

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Richuen22 2002-06-17

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http://www.csdn.net/expert/topic/527/527091.xml?temp=.1015131

xuying 2002-06-16

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/*************************************************************
* smtp.cpp - Use SMTP to send an eMail with an Attachment and verify *
* Copyright (C) 2001-2002 by ShadowStar. *
* Use and modify freely. *
* http://shadowstar.126.com/ *
*************************************************************
*/
//---------------------------------------------------------------------------

#include <winsock2.h>
#include <string.h>
#include <stdio.h>

const int BASE64_MAXLINE = 76;
const char EOL[] = "\r\n";
const char BASE64_TAB[] = "ABCDEFGHIJKLMNOPQRSTUVWXYZ"
"abcdefghijklmnopqrstuvwxyz0123456789+/";
const char HEADER[] =
"HELO support.com\r\n"
//"AUTH LOGIN\r\n" //+ BASE64 USER + BASE64 PASS
"MAIL FROM: chinansl@support.com\r\n"
"RCPT TO: shadowstar@support.com\r\n"
"DATA\r\n"
"FROM: chinansl@support.com\r\n"
"TO: shadowstar@support.com\r\n"
"SUBJECT: this is a test\r\n"
"Date: 2002-5-14\r\n"
"X-Mailer: shadowstar's mailer\r\n"
"MIME-Version: 1.0\r\n"
"Content-type: multipart/mixed; boundary=\"#BOUNDARY#\"\r\n"
//"Content-Type: text/plain; charset=gb2312\r\n"
"\r\n";
const char CONTENT[] =
"\r\n--#BOUNDARY#\r\n"
"Content-Type: text/plain; charset=gb2312\r\n"
"Content-Transfer-Encoding: quoted-printable\r\n"
"\r\n"
"/*************************************************************"
" * smtp.cpp - Use SMTP to send an eMail with an Attachment and verify *"
" * Copyright (C) 2001-2002 by ShadowStar. *"
" * Use and modify freely. *"
" * http://shadowstar.126.com/ *"
" *************************************************************"
" */\r\n"
"\r\n";
const char ATT_HEADER[] =
"\r\n--#BOUNDARY#\r\n"
"Content-Type: application/octet-stream; name=smtp.exe\r\n"
"Content-Disposition: attachment; filename=smtp.exe\r\n"
"Content-Transfer-Encoding: base64\r\n"
"\r\n";

//---------------------------------------------------------------------------
int ANSIToBase64(const char *szInANSI, int nInLen, char *szOutBase64, int nOutLen);

int main(int argc, char* argv[])
{
WSADATA wsaData;
int SockFD;
struct sockaddr_in ServAddr;
char buf[0x100];
int x;
FILE *fp;
char *aatt = new char[0x400000];
char *batt = new char[0x555556];

WSAStartup(MAKEWORD(2,2), &wsaData);

LPHOSTENT pHost = gethostbyname("172.16.234.111");
SockFD = socket(AF_INET, SOCK_STREAM, IPPROTO_TCP);
ServAddr.sin_family = AF_INET;
ServAddr.sin_addr.s_addr = *(ULONG *)pHost->h_addr_list[0];
ServAddr.sin_port = htons(25);

connect(SockFD, (struct sockaddr *)&ServAddr, sizeof(ServAddr));
//send HEADER
send(SockFD, HEADER, strlen(HEADER), 0);
//send CONTENT
send(SockFD, CONTENT, strlen(CONTENT), 0);
//send ATT_HEADER
send(SockFD, ATT_HEADER, strlen(ATT_HEADER), 0);
//read attachment
fp = fopen(argv[0], "rb");
fseek(fp, 0, 2);
x = ftell(fp);
if (x > 0x400000)
x = 0;
rewind(fp);
fread(aatt, x, 1, fp);
fclose(fp);
x = ANSIToBase64(aatt, x, batt, 0x555556);
//send base64 attachment
send(SockFD, batt, x, 0);

send(SockFD, ".\r\n", strlen(".\r\n"), 0); //end
send(SockFD, "QUIT\r\n", strlen("QUIT\r\n"), 0); //quit

closesocket(SockFD);
WSACleanup();

delete []aatt;
delete []batt;
return 0;
}
//---------------------------------------------------------------------------
int ANSIToBase64(const char *szInANSI, int nInLen, char *szOutBase64, int nOutLen)
{
//Input Parameter validation
if ((szInANSI == NULL) || (nInLen == 0) || (szOutBase64 == NULL) || (nOutLen == 0))
return 0;
if (nOutLen < (nInLen*4/3 + 1 + nInLen*4/3/BASE64_MAXLINE*2 + 1 + 4))
return 0;

//Set up the parameters prior to the main encoding loop
int nInPos = 0;
int nOutPos = 0;
int nLineLen = 0;
int c1, c2, c3;
int i;

// Get three characters at a time from the input buffer and encode them
for (i=0; i<nInLen/3; ++i)
{
//Get the next 2 characters
c1 = szInANSI[nInPos++] & 0xFF;
c2 = szInANSI[nInPos++] & 0xFF;
c3 = szInANSI[nInPos++] & 0xFF;

//Encode into the 4 6 bit characters
szOutBase64[nOutPos++] = BASE64_TAB[c1 >> 2];
szOutBase64[nOutPos++] = BASE64_TAB[((c1 << 4) | (c2 >> 4)) & 0x3F];
szOutBase64[nOutPos++] = BASE64_TAB[((c2 << 2) | (c3 >> 6)) & 0x3F];
szOutBase64[nOutPos++] = BASE64_TAB[c3 & 0x3F];
nLineLen += 4;

//Handle the case where we have gone over the max line boundary
if (nLineLen > BASE64_MAXLINE - 4)
{
szOutBase64[nOutPos++] = EOL[0];
szOutBase64[nOutPos++] = EOL[1];
nLineLen = 0;
}
}

// Encode the remaining one or two characters in the input buffer
switch (nInLen % 3)
{
case 0:
{
szOutBase64[nOutPos++] = EOL[0];
szOutBase64[nOutPos++] = EOL[1];
break;
}
case 1:
{
c1 = szInANSI[nInPos] & 0xFF;
szOutBase64[nOutPos++] = BASE64_TAB[(c1 & 0xFC) >> 2];
szOutBase64[nOutPos++] = BASE64_TAB[((c1 & 0x03) << 4)];
szOutBase64[nOutPos++] = '=';
szOutBase64[nOutPos++] = '=';
szOutBase64[nOutPos++] = EOL[0];
szOutBase64[nOutPos++] = EOL[1];
break;
}
case 2:
{
c1 = szInANSI[nInPos++] & 0xFF;
c2 = szInANSI[nInPos] & 0xFF;
szOutBase64[nOutPos++] = BASE64_TAB[(c1 & 0xFC) >> 2];
szOutBase64[nOutPos++] = BASE64_TAB[((c1 & 0x03) << 4) | ((c2 & 0xF0) >> 4)];
szOutBase64[nOutPos++] = BASE64_TAB[((c2 & 0x0F) << 2)];
szOutBase64[nOutPos++] = '=';
szOutBase64[nOutPos++] = EOL[0];
szOutBase64[nOutPos++] = EOL[1];
break;
}
default:
{
return 0;
}
}

szOutBase64[nOutPos] = 0;

return nOutPos;
}

nuaawyd 2002-06-16

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nuaawyd 2002-06-16

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wjlcq 2002-06-16

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我已到masterz()指点的地方找到了代码，先学习一下，解决了问题就来加分

vcc2002 2002-05-13

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vcc2002 2002-05-13

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masterz 2002-05-13

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http://www.naughter.com/smtp.html
Fully supports AUTH CRAM-MD5, AUTH LOGIN and AUTH LOGIN PLAIN authentication methods.

xuying 2002-05-13

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发送的时候如果服务器不需要身份认证，也可以不要密码。
你还是先看一下SMTP协议再编程序吧。

你可以用
c:\>telnet your_smtp_server 25

来学习如何用SMTP与服务器通信。

freelybird 2002-05-13

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java的，要不要

tianlinyi 2002-05-13

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我有这样的smtp程序

你要的话TIANLINYI@SINA.COM

一个问题问两次！200分等待高手！

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