菜鸟问题系列之三

65536 2002-07-19 08:12:04
请教一笔画的算法,就是给出一个图,如果能一笔画出的话,要一个算法给出画法.
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许野平 2002-07-19
呵呵,这是图论里面的最基本的一个问题。主要判定依据奇数边的定点个数不能超过两个。
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atlantis13579 2002-07-19

http://cpp.chinaccd.net/bbs/showthread.php?s=&threadid=177
【题目16】
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LeeMaRS 2002-07-19
看看这篇文章,来自USACO.
Eulerian Tour
Sample Problem: Riding The Fences
Farmer John owns a large number of fences, which he must periodically check for integrity. Farmer John keeps track of his fences by maintaining a list of their intersection points, along with the fences which end at each point. Each fence has two end points, each at an intersection point, although the intersection point may be the end point of only a single fence. Of course, more than two fences might share an endpoint.

Given the fence layout, calculate if there is a way for Farmer John to ride his horse to all of his fences without riding along a fence more than once. Farmer John can start and end anywhere, but cannot cut across his fields (the only way he can travel between intersection points is along a fence). If there is a way, find one way.

The Abstraction
Given: An undirected graph

Find a path which uses every edge exactly once. This is called an Eulerian tour. If the path begins and ends at the same vertex, it is called a Eulerian circuit.

The Algorithm
Detecting whether a graph has an Eulerian tour or circuit is actually easy; two different rules apply.

A graph has an Eulerian circuit if and only if it is connected (once you throw out all nodes of degree 0) and every node has `even degree'.
A graph has an Eulerian path if and only if it is connected and every node except two has even degree.
In the second case, one of the two nodes which has odd degree must be the start node, while the other is the end node.
The basic idea of the algorithm is to start at some node the graph and determine a circuit back to that same node. Now, as the circuit is added (in reverse order, as it turns out), the algorithm ensures that all the edges of all the nodes along that path have been used. If there is some node along that path which has an edge that has not been used, then the algorithm finds a circuit starting at that node which uses that edge and splices this new circuit into the current one. This continues until all the edges of every node in the original circuit have been used, which, since the graph is connected, implies that all the edges have been used, so the the resulting circuit is Eulerian.

More formally, to determine a Eulerian circuit of a graph which has one, pick a starting node and recurse on it. At each recursive step:

Pick a starting node and recurse on that node. At each step:
If the node has no neighbors, then append the node to the circuit and return
If the node has a neighbor, then make a list of the neighbors and process them (which includes deleting them from the list of nodes on which to work) until the node has no more neighbors
To process a node, delete the edge between the current node and its neighbor, recurse on the neighbor, and postpend the current node to the circuit.
And here's the pseudocode:
# circuit is a global array
find_euler_circuit
circuitpos = 0
find_circuit(node 1)

# nextnode and visited is a local array
# the path will be found in reverse order
find_circuit(node i)

if node i has no neighbors then
circuit(circuitpos) = node i
circuitpos = circuitpos + 1
else
while (node i has neighbors)
pick a random neighbor node j of node i
delete_edges (node j, node i)
find_circuit (node j)
circuit(circuitpos) = node i
circuitpos = circuitpos + 1

To find an Eulerian tour, simply find one of the nodes which has odd degree and call find_circuit with it.

Both of these algorithms run in O(m + n) time, where m is the number of edges and n is the number of nodes, if you store the graph in adjacency list form. With larger graphs, there's a danger of overflowing the run-time stack, so you might have to use your own stack.
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ynli2002 2002-07-19
这与《数据结构》里的走迷宫算法类似!
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