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救命，帮忙看一下asp的这个语法的问题
<%
strSql = "select * from ghxjArticle where id =" & "'" & idnew & "'"
set rs = mycon.execute(strSql)
%>
<%strTest = rs("ArticleContent")%>
<%response.replace("strTest", "chr(13)", "<br>")%>
<% response.write strTest%>
目的就是将rs("ArticleContent")中的chr(13)替换成<br>
strSql = "select * from ghxjArticle where id =" & "'" & idnew & "'"
set rs = mycon.execute(strSql)
%>
<%strTest = rs("ArticleContent")%>
<%response.replace("strTest", "chr(13)", "<br>")%>
<% response.write strTest%>
目的就是将rs("ArticleContent")中的chr(13)替换成<br>
...全文
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miles_z 2002-07-27
麻烦。要<ENTER>，直接vbcrlf不就结了。
strTest = replace(strTest,vbCrlf,"<br>")
strTest = replace(strTest,vbCrlf,"<br>")
dfymdweb 2002-07-27
我同意梦之旅的说法
.....
strSql = "select * from ghxjArticle where id =" & idnew
......
<%strTest = replace(strTest,chr(10)&chr(13),"<br>")%>
.......
.....
strSql = "select * from ghxjArticle where id =" & idnew
......
<%strTest = replace(strTest,chr(10)&chr(13),"<br>")%>
.......
tripofdream 2002-07-27
如果id是数值型的
......
strSql = "select * from ghxjArticle where id =" & idnew
......
<%strTest = replace(strTest,chr(13)&chr(10),"<br>")%>
......
......
strSql = "select * from ghxjArticle where id =" & idnew
......
<%strTest = replace(strTest,chr(13)&chr(10),"<br>")%>
......
topfistcn 2002-07-27
注意asp中的变量和字符串的表示，strTest表示变量，而“strTest”表示字符串
jisi 2002-07-26
<%
strSql = "select * from ghxjArticle where id =" & "'" & idnew & "'"
set rs = mycon.execute(strSql)
%>
<%strTest = rs("ArticleContent")%>
<%strTest = replace(strTest, chr(13), "<br>")%>
<% response.write strTest%>
strSql = "select * from ghxjArticle where id =" & "'" & idnew & "'"
set rs = mycon.execute(strSql)
%>
<%strTest = rs("ArticleContent")%>
<%strTest = replace(strTest, chr(13), "<br>")%>
<% response.write strTest%>
JavaCoffee 2002-07-26
将其中的一句代码：
<%response.replace("strTest", "chr(13)", "<br>")%>
换成：
<%response.replace(strTest, chr(13), "<br>")%>
即可。
<%response.replace("strTest", "chr(13)", "<br>")%>
换成：
<%response.replace(strTest, chr(13), "<br>")%>
即可。