一个非常简单的,获得本机日期的问题

gxbhhp 2002-08-06 10:43:19
<script language=javascript>
function UTCTimeDemo(){
var d, s = "日期是 (UTC) is: ";
var c = ":";
d = new Date();
s += d.getUTCHours() + c;

s += d.getUTCMilliseconds();
return(s);
}
alert(UTCTimeDemo());
</script>

这个可以获得几点几点,可是,我想获得日期,就是年月日,怎么改:d.getUTCHours() ?
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切换为时间正序
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willway 2002-08-12
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up,getUTCDate
flylyke 2002-08-12
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给你个最完整的.这是前几天刚做完的
<html>
<body>
<script>
var dayarray=new Array("Sunday","Monday","Tuesday","Wednesday","Thursday","Friday","Saturday")
var montharray=new Array("January","February","March","April","May","June","July","August","September","October","November","December")

function getthedate(){
var mydate=new Date()
var year=mydate.getUTCFullYear()
if (year < 1000)
year+=1900
var day=mydate.getUTCDay()
var month=mydate.getUTCMonth()
var daym=mydate.getUTCDate()
if (daym<10)
daym="0"+daym
var hours=mydate.getUTCHours()
var minutes=mydate.getUTCMinutes()
var seconds=mydate.getUTCSeconds()
var dn="AM"
if (hours>=12)
dn="PM"
if (hours>12){
hours=hours-12
}
if (hours==0)
hours=12
if (minutes<=9)
minutes="0"+minutes
if (seconds<=9)
seconds="0"+seconds
//change font size here
var Bj=8;
//var Bjstr=parseInt(Bj);
var cdate="<small><font color='000000' face='Arial'><b>"+dayarray[day]+", "+montharray[month]+" "+daym+", "+year+" "+hours+":"+minutes+":"+seconds+" "+dn
var Bjdate="<small><font color='000000' face='Arial'><b>"+dayarray[day]+", "+montharray[month]+" "+daym+", "+year+" "+(hours+Bj)+":"+minutes+":"+seconds+" "+dn
+"</b></font></small>"
if (document.all){
document.all.clock1.innerHTML=cdate;
document.all.clock2.innerHTML=Bjdate;}
//return(cdate);
else
document.write(cdate)
}
if (!document.all)
getthedate()
function goforit(){
if (document.all)
setInterval("getthedate()",1000)
}

</script>
<font color='000000' face='Arial'><b>格林尼治时间:</b></font><span id="clock1"><script>goforit();</script></span><br>
<font color='000000' face='Arial'><b>北京时间:</b></font><span id="clock2"><script>goforit();</script></span>
</body>
</html>
saucer 2002-08-06
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d.getUTCFullYear()

d.getUTCFullMonth() + 1

d.getUTCDate()


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