写个正则,帮忙?

[95306]

[abc]asdfasldkfjlasd[/abc]

怎么把[abc][/abc]变为空的

[Reve]

不是很清楚“怎么把[abc][/abc]变为空的”，估计是我下边的第二种replace的方法：
<script>
function blacketReplace1(str)
{
var tmpstr = "";
while (tmpstr != str) {
tmpstr = str;
str = str.replace(/\[([^\]]*)\]([^\[]*)\[\/([^\[]*)\]/g,
function($0,$1,$2,$3,$4,$5,$6,$7,$8,$9,$10) {
return "[" + $1 + "][/" + $3 + "]";
});
}
return str;
}
str = "[abc]dfsdfds[/abc][fdls]";
alert(blacketReplace1(str));


function blacketReplace(str)
{
var tmpstr = "";
while (tmpstr != str) {
tmpstr = str;
str = str.replace(/(\[)([^\]]*)(\])([^\[]*)(\[\/)([^\[]*)(\])/g,
function($0,$1,$2,$3,$4,$5,$6,$7,$8,$9,$10) {
return $4;
});
}
return str;
}

str = "[abc]dfsdfds[/abc][fdls]";
alert(blacketReplace(str));

</script>

[Reve]

感觉上边的表达式应该可以写的简洁点，不过那是我接触表达式不久时写的，现在不高兴修理了。：）

[95306]

是呀,太长了吧,兄弟再帮改改

[qiushuiwuhen]

/\[([^\]]+)\]([^[]+)\[\/\1\]/g
<script>
str="[abc]asdfasldkfjlasd[/abc]"
str=str.replace(/\[([^\]]+)\]([^[]+)\[\/\1\]/g,"$2");
alert(str);
</script>

[qiushuiwuhen]

高版本可用
<script>
str="[abc]asdfasldkfjlasd[/abc]"
str=str.replace(/\[(.+?)\](.+?)\[\/\1\]/g,"$2");
alert(str);
</script>